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MrRa [10]
3 years ago
13

This is hard help is needed

Mathematics
1 answer:
SOVA2 [1]3 years ago
6 0
You have to graph the first one so you would do total cost=1.25*lb
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Simplify the following expression.<br> 5 [13 + 10 = (3 + 2)] + 9 x 2
Sergio [31]

Answer:

i BELIEVE ITS

Step-by-step explanation:

5 [13 + 10 = (3 + 2)] + 9 x 2

65+50=25+18

115=43

7 0
3 years ago
Y = x + 3<br>2y = 2x + 6​
Marina CMI [18]

Answer:

x=0

y=3

Step-by-step explanation:

2(x+3)=2x+6, substituting the first equation in the second

2x+6=2x+6, rearranging the equations

2x-2x=6-6

0=0

y=0+3

y=3

6 0
3 years ago
A parking lot charges $3 to park a car for the first hour and $2 per hour after that. If you use more than one parking space, th
fenix001 [56]
Consider the charge for parking one car for t hours.

If t is more than 1, then the function is y=3+2(t-1), because 3 $ are payed for the first hour, then for t-1 of the left hours, we pay 2 $.

If t is one, then the rule y=3+2(t-1) still calculates the charge of 3 $, because substituting t with one in the formula yields 3.


75% is 75/100 or 0.75. 

For whatever number of hours t, the charge for the first car is 3+2(t-1) $, and whatever that expression is, the price for the second car and third car will be 

0.75 times 3+2(t-1). Thus, the charge for the 3 cars is given by:

3+2(t-1)+0.75[3+2(t-1)]+0.75[3+2(t-1)]=3+2(t-1)+<span>0.75 × 2[3 + 2(t − 1)].


Thus, the function which total parking charge of parking 3 cars for t hours is:

</span><span>f(t) = (3 + 2(t − 1)) + 0.75 × 2(3 + 2(t − 1)) 


Answer: C</span>
4 0
3 years ago
Victoria and Georgetown are 67.2 miles from each other. How far apart would the cities be on a map that has a scale of 0.9 inche
Artemon [7]

Answer: 5.76 miles

Step-by-step explanation:

Let the distance between Victoria and Georgetown on the map be represented by x.

The information given in the question can then be formed into an expression which will be:

0.9/x = 10.5/67.2

Cross multiply

(10.5 × x) = 67.2 × 0.9

10.5x = 60.48

x = 60.48/10.5

x = 5.76

The answer is 5.76 miles

7 0
3 years ago
Simplify the exponential expression <br> A- 5cdf<br> B- 60cdf<br> C- 60cdf <br> D- 5cdf
jekas [21]
------------------------------
(75c^2d^4f^8)/(15cd^3f^4)

75/15 x c^2d^4f^8 over cd^3f^4

5 x c^2d^4f^8 over cd^3f^4

5c^2-1d^4-3f^8-4

5c^1d^4-3f^8-4

5c^1d^1f^8-4

5c^1d^1f^4

5cd^1f^4

5cdf^4 or option A.
------------------------------
5 0
3 years ago
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