Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Answer:
0≥x<4
Step-by-step explanation:
first, let's look at this number line.
there is a closed circle at 0 and an open circle at 4. this means that 0 is included (≤ or ≥) and that 4 is not included (< or >).
these are the endpoints, meaning that in this compound inequality, the numbers next to the symbols are 0 and 4.
x is in the middle of this compound inequality.
0 x 4
now, we have to figure out the symbols in between. i wrote out our choices above for each number. the highlighted portion is greater than or equal to 0 and less than 4, so we can write this compound inequality as the following:
0≥x<4
x is greater than or equal to 0, but less than 4
62 percent of 80 is more
Step-by-step explanation:
the 62 percent of 80 comes out to 49.6 people and the other one comes out to 42 people
i dont know how to explain how to do it
Answer:
Step-by-step explanation:
You need to specify what the goal of the problem is.
If Kai picked 7 times as many blueberries as Nico, then:
n + 7n + 297, or
8n = 297. Unfortunately, 8 does not divide evenly into 297, and we certainly are not interested in picking fractional blueberries.
If the problem mentioned 296 instead of 297 total blueberries, then
Nico (n) picked 47 blueberries and Kai picked 7 times that many, or 329.
