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leva [86]
3 years ago
9

2x3 + 3x + 4 I’m so lost rn.. somebody please help me

Mathematics
1 answer:
VikaD [51]3 years ago
6 0

Answer: My answer was wrong sorry

Step-by-step explanation:

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What is 24% of 1350 I will give 75 points
nika2105 [10]
<h3>Answer:</h3><h2>324.</h2><h3>Step-by-step explanation:</h3>

To find 24% of 1,350, you must multiply 24% by 1,350.

To do this problem, we must turn the numbers to fractions.

Twenty-Four hundredths, 24 / 100 is your fraction for 24%.

Put 1,350 over 1 since 1,350 is a whole number.

So:

24 / 100 x 1,350 / 1.

1350 x 24 = 32400, 100 x 1 = 100.

Your answer is 32,400 / 100.

Get rid of the 2 zeroes in 400 and 100.

It should be 324 / 1.

Since 1 is just the number 1, the answer is 324.

If you have any questions, feel free to comment below.

Merry Christmas!

8 0
3 years ago
Read 2 more answers
The product of two consecutive positive integers is greater than their sum by 209. Find these numbers.
Delicious77 [7]

Answer:

I think it is -4 and -3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve.
bixtya [17]

Answer:

-3 ± 2\sqrt{3} = x

Step-by-step explanation:

x² + 6x + 9 = 12 → x² + 6x - 3

Since this Quadratic Expression is unfactorable, apply the <em>Quadratic</em><em> </em><em>Formula</em>:

x = -b ± \frac{\sqrt{{b}^{2} - 4ac}}{2a}

-6 ± \frac{\sqrt{{6}^{2} - 4(1)(-3)}}{2(1)} =   -6 ± \frac{\sqrt{36 + 12}}{2} = -6 ± \frac{\sqrt{48}}{2} \\ \\ -3 ± 2\sqrt{3}

√48 = √[3 × 16] = 4√3

½[4√3] = 2√3

Then attach half of -6 to it as well [-3]:

-3 ± 2√3

I am joyous to assist you anytime.

7 0
3 years ago
If a rectangle has a length of 4 square root of 2 and a width of 7 square root of 18 what
Orlov [11]

Answer:8^4 + 14^36 is the perimeter because they are for sides in a rectangle so you have to double the amount.

7 0
3 years ago
Twenty times a square of a positive integer plus 50 equals negative 40 times the square of the positive integer plus one-hundred
rusak2 [61]
20x^2+50 = -40x^2+110x [ Taking x as the unknown positive integer ]
4 0
3 years ago
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