A = lw
Plug in what we know:
25/54 = (5/9)w
Divide 5/9 to both sides or multiply by its reciprocal, 9/5:
25/54 * 9/5 = w
Multiply the numerators and denominators together:
225/270 = w
Simplify:
<span>w = 5/6</span>
Answer:
h=6
Step-by-step explanation:
19h-7=23+14h
-7-23=14h-19h
-30=-5h
h=6
15 16 and then 17 to be an equilateral
Answer:
No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.
For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.
2
in.
+
3
in.
=
5
in.
5
in.
<
6
in.
For a triangle with sides 3 in., 4 in. and 5 in. which can form a triangle:
3 + 4 = 7 which is greater than 5
3 + 5 = 8 which is greater than 4
4 + 5 = 9 which is greater than 3
Step-by-step explanation:
