A what is a positive whole number greater than 1 that has only one and itself as factors?

mezya [45]

Answer:

x = 7000

y = 5600

(7000, 5600)

Step-by-step explanation:

To solve the system of equations means to find the point of intersection (graphically). You are finding what value of 'x' and what value of 'y' fits both equations.

x = y + 1400

0.08x + 0.05y = 840

We can solve using the method <u>substitution</u>, where you replace a variable in one equation with an equivalent expression.

<u>Since "x" is y + 1400, we can replace "x" in the second equation.</u>

0.08x + 0.05y = 840

0.08(y + 1400) + 0.05y = 840

Distribute over brackets by multiplying 0.08 with y, then 0.08 with 1400.

0.08y + 112 + 0.05y = 840 Collect like terms (with "y" variable)

112 + 0.13y = 840

Now isolate "y" in the simplified equation.

112 - 112 + 0.13y = 840 - 112 Subtract 112 from both sides

0.13y = 728

0.13y/0.13 = 728/0.13 Divide both sides by 0.13

y = 5600 Solved for y

We can substitute "y" with 5600 in any other equation that has "x".

x = y + 1400

x = 5600 + 1400 Add

x = 7000 Solved for x

You may express the answer as a coordinate, or an ordered pair (x, y).

The solution is (7000, 5600).

3 0

4 years ago

Read 2 more answers

In Chicago, Illinois, the temperature was -14°F in the morning. If the

Rom4ik [11]

Answer:

-20° F

Step-by-step explanation:

the temperature would be :

=》-14 - 6 = -20° F

7 0

3 years ago

Read 2 more answers

What is the value of x

katrin [286]

the full arc is 176

so subtract 110 from 176

176-110 = 66

x = 66 degrees

7 0

3 years ago

Frank has a 2-digit number on his baseball uniform. the number is a multiple of 10 and has 3 for one its factors. what three num

Feliz [49]

A. What three numbers could possibly be on his uniform.
B. Probability of being a multiple of 10 and is two digits and has a 3 as a factor.
C. Frank has a 30 on his uniform. The number is a multiple of 10 and one factor of the number is 3.

4 0

3 years ago

The computer center at Dong-A University has been experiencing computer down time. Let us assume that the trials of an associate

Schach [20]

Answer:

(a)0.16

(b)0.588

(c) $[s_1$ s_2]=[0.75,$ 0.25]$

Step-by-step explanation:

The matrix below shows the transition probabilities of the state of the system.

$\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

(a)To determine the probability of the system being down or running after any k hours, we determine the kth state matrix $P^k$ .

(a)

$P^1=\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

$P^2=\begin{pmatrix}0.84&0.16\\ 0.48&0.52\end{pmatrix}$

If the system is initially running, the probability of the system being down in the next hour of operation is the $(a_{12})th$ entry of the P^2$ matrix.$

The probability of the system being down in the next hour of operation = 0.16

(b)After two(periods) hours, the transition matrix is:

$P^3=\begin{pmatrix}0.804&0.196\\ 0.588&0.412\end{pmatrix}$

Therefore, the probability that a system initially in the down-state is running

is 0.588.

(c)The steady-state probability of a Markov Chain is a matrix S such that SP=S.

Since we have two states, $S=[s_1$ s_2]$

$[s_1$ s_2]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[s_1$ s_2]$

Using a calculator to raise matrix P to large numbers, we find that the value of $P^k$ approaches [0.75 0.25]:

Furthermore,

$[0.75$ 0.25]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[0.75$ 0.25]$

The steady-state probabilities of the system being in the running state and in the down-state is therefore:

$[s_1$ s_2]=[0.75$ 0.25]$

4 0

4 years ago