Answer:
Step-by-step explanation:
One way to determine if the equation has any real solutions is to look at its discriminant. For the equation ax²+bx+c = 0, the discriminant is ...
d = b² -4ac
When the discriminant is negative, both solutions to the quadratic are complex. There are no real solutions in that case.
We can find the discriminant values to be ...
A: d = 2² -4(1)(4) = -12 . . . . no real zeros
B: d = 0² -4(3)(-5) = 60 . . . two real zeros
C: d = 8² -4(-2)(0) = 64 . . . two real zeros
D: d = 10² -4(1)(26) = -4 . . .no real zeros
Expressions A and D have no real zeros.
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<em>Comment on the question</em>
You are given an <em>expression</em>, not an <em>equation</em>. There is no equal sign. Hence, we cannot talk about <em>solutions</em>. We can only talk about <em>zeros</em>, values of x that make the expression have a value of zero.
Five dot twelve
ninedyfour dot zerozerothree
Answer:
N(11 , 13)
Step-by-step explanation:
M(3,4) = (x,y)
A(-5, -5) = (x1,y1)
N ( )=(x2,y2)
using midpoint formula;
M(x,y)=(x1 + x2)/2 , (y1 + y2)/2
(3,4)= (-5 + x2)/2 , (-5 + y2)/2
Now;
3 = (-5+x2)/2 4 = (-5 +y2)/2
6 = -5 +x2 8 = -5 +y2
6+5 = x2 8+5=y2
x2=11 y2 = 13
Answer:
B
Step-by-step explanation:
In a function, every x-coordinate must be a different number.
If the same number appears more than once as an x-coordinate, it is not a function.
Answer: B
Answer:
Josie and Emmanuel are the same.
Step-by-step explanation:
By pluggin the numbers given into the equations, you find that Josie and Emmanuel are 5/8 while Maria is 120.
