<h3>(3x-2)(2x²+x+5)</h3><h3>3x (2x²+x+5) -2 (2x²+x+5)</h3><h3>6x³+3x²+15x-4x²-2x-10</h3><h3>6x³+3x²-4x²+15x-2x-10</h3><h3>6x³-x²+13x-10</h3><h3>this is the answer may u like it and hope full it will be the correct</h3>
please mark this answer as brainlist
26 maybe it can be ım not sure
Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Step-by-step explanation:
all......................
Answer: The answer is 1/21
Step-by-step explanation:
