This is an exponential decay problem.
Using the equation Y = a *(1-rate)^time
where Y is the future value given as 12,000 and a is the starting value given as 13,000.
The rate is also given as 5%.
The equation becomes:
12,000 = 13,000(1-0.05)^x
12,000 = 13,000(0.95)^x
Divide each side by 13000:
12000/13000 = 0.95^x/13000
12/13 = 0.95^x
Use the natural log function:
x = ln(12/13) / ln(0.95)
x = 1.56 years. ( this will equal 12,000
Round to 2 years it will be less than 12000.
Answer:
the transistors have L=1 mm of linear size
Step-by-step explanation:
For the silicon chip the area is A=1 cm² and for the transistors the area is At=L² (L=linear size) . Then since N= 10 billion transistors of area At should fit in the area A
A=N*At
A=N*L²
solving for L
L= √(A/N)
Assuming that 1 billion=10⁹ (short scale version of billion), then
L= √(A/N) = √(1 cm²/10⁹) = 1 cm / 10³ = 1 mm
then the transistors have L=1 mm of linear size
18). 16:80 is the ratio but in simplest form is; 5:0
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hope that helps:D