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3 years ago

Is there a smallest decimal that is greater than the number 2? Explain your answer.

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

8 0

Answer:

Technically, yes. It's called epsilon, which is defined as an infinitely small number. So

2 + epsilon is the smallest number greater than 2. But for practical purposes no there isn't.

Step-by-step explanation:Not without limits. You can always move the .1 one place further from the interring. For example,

2.1>2.01

and

2.01>2.001

So, unless there are a limited number of decimal spaces, you can continually add an infinite amount of zeros behind the decimal point, followed by a one.

If you use two or three decimal spaces as a standard in your class, then the smallest decimal greater than 2 would be 2.01 or 2.001, respectively.

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What is the equation of this graphed line?

Levart [38]

Answer:

sorry dont know!!

Step-by-step explanation:

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3 years ago

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I need help again.lol

Monica [59]

Answer:

$13\ units$

Step-by-step explanation:

One is asked to find the distance between two points on a coordinate plane. The easiest way to do so is to use the distance formula, this formula is the following:

$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2$

Where ( $(x_1,y_1)$ ) and ( $(x_2,y_2)$ ) are the points which one needs to find the distance between. In this case, these points are as follows:

$k\ (-3,5)$

$j\ (-8, -7)$

Substitute these points into the formula and solve for the distance between these points,

$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2$

$D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2$

Simplify,

$D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2$

$D=\sqrt{(-3+8)^2+(5+7)^2$

$D=\sqrt{(5)^2+(12)^2$

$D=\sqrt{25+144}$

$D=\sqrt{169}$

$D=13$

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2 years ago

A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides

ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

=(15-2x)(10-2x)x cubic inches

=(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ , here a=12, b= -100 and c=15

$x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}$

$\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}$

$\Rightarrow x=0.1528,8.18$

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, $V''|_{x=0.1528}=24(0.1528)-100$

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box has largest volume.

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3 years ago

Solve x2 – 8x + 15 < 0.

rusak2 [61]

X2 - 8x + 15 = 0
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mr Goodwill [35]

Answer:

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3 years ago