Answer:
Heights of 29.5 and below could be a problem.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.
This means that 
There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.
Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus


Heights of 29.5 and below could be a problem.
Answer:

Step-by-step explanation:


















Hence, the correct answer is 
Answer:
<h2>A. y = 3x - 2</h2>
Step-by-step explanation:
The slope-intercept form of an equation of a line:
<em>y = mx + b</em>
<em>m</em><em> - slope</em>
<em>b</em><em> - y-intercept</em>
<em />
We have
<em>A. y = 3x - 2 - it's the slope-intercept form</em>
<em>B. x = 1/2y + 8 </em><em>NOT</em>
<em>C. 2x + 5y = 12 </em><em>NOT</em><em> - it's the standard form</em>
<em>D. 3y = 8x - 5 </em><em>NOT</em>
Sin^(1/2) x cos x - sin^(5/2) cos x
= sin^(1/2) x cos x - sin(1/2)x sin^2 x cos x
factoring we get:
cos x sin^(1/2) x ( 1 - sin^2 x)
Now 1 - sin^2 x = cos^2 x so we have
cos x sin^(1/2) x * cos^2 x
= cos^3 x sqrt sin x
Answer:
C. The value of f (4) is 60, and it represents the number of hours of work remaining for the month after working for 4 days
Step-by-step explanation:
So 5 time 4 equals 20...!
80 minus 20= 60