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3 years ago

Nine raised to the five-minus-two power?

Mathematics

1 answer:

bonufazy [111]3 years ago

8 0

Answer:

1. 9 raised to the third power is 729

2. 4 raised the the power of 1 is 1

Step-by-step explanation:

9*9= 81*9=729

4*1=4

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You have a 1-gallon paint can in the shape of a cylinder. One gallon is 231 cubic inches. The radius of the can is 3 inches. Wha

aleksandr82 [10.1K]

Answer:

The approximate height of the paint can is 8.2 in

Step-by-step explanation:

we know that

The volume of the cylinder ( can of paint) is equal to

$V=\pi r^{2} h$

we have

$V=231\ in^{3}$

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Substitute the values and solve for h

231=(3.14)(3)^{2} h

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3 years ago

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50 points for answer.

noname [10]

Answer:

Point C: (4, 0)

Step-by-step explanation:

Parallelograms are quadrilaterals with two pairs of parallel sides, this means they will have the same slope between two line segments.

point slope form between two points: y - y1 = m (x - x1)

point A (2, 6) and D (4,4):

slope: point form, 6 - 4 = m(2 - 4)

2 = -2m

m (slope) = $\frac {2}{-2}$ = $\frac {Change in X position}{ Change in Y position}$

now that you know the change in position, apply this to vertice B to get the position of the final vertice.

B(2, 2)

C (2 +2, 2-2) = C(4, 0)

The final position of C vertice for parrallelogram A(2,6), B(2,2), D(4,4) will be C(4,0)

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3 years ago

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Please solve this fast

Korolek [52]

Step-by-step explanation:

$qr - pr \: + qs - ps$

$r(q - p) + s(q - p)$

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$axy + bcxy - az - bcz$

$xy(a + bc) - z(a + bc)$

$(xy - z)(a + bc)$

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3 years ago

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Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag

VLD [36.1K]

$Hey~freckledspots!\\----------------------$

$We~will~solve~for~i^{425}!$

$Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\$

$Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------$

$Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------$

$Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------$