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3 years ago

Need help soon as possible taking a test

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

8 0

Answer:

Step-by-step explanation:

A|B (A given b)= (A and b)/b

Sore throat|Fever= sore throatand fever/fever

.21/.7= .3

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What is the area of a rectangle with vertices at (0, −4) , (−1, −3) , (2, 0) , and (3, −1) ? Enter your answer in the box

Bad White [126]

We are given vertices of a rectangle (0, −4) , (−1, −3) , (2, 0) , and (3, −1).

Length is the distance between (0, −4) and (−1, −3) points.

Width is distance between (−1, −3) and (2, 0) points.

<u>Computing length:</u>

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-1-0\right)^2+\left(-3-\left(-4\right)\right)^2}$

$=\sqrt{2}$

<u>Computing Width :</u>

$\mathrm{The\:distance\:between\:}\left(-1,\:-3\right)\mathrm{\:and\:}\left(2,\:0\right)\mathrm{\:is\:}$

$=\sqrt{\left(2-\left(-1\right)\right)^2+\left(0-\left(-3\right)\right)^2}$

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<h3>Area of the rectangle = Length × Width </h3>

= $\sqrt{2} \times 3\sqrt{2} = 3 \times 2 = 6 \ squares \ units.$ .

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sukhopar [10]

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