Since this is a combination not a permutation problem, (order does not matter) you should use the "n choose k" formula.
C=n!/(k!(n-k)!) where C is the number of unique combinations, n equals the total number of possible choices and k equals the specific number of choices. In this case:
C=9!/(4!(9-4)!)
C=9!/(4!5!)
C=362880/(24*120)
C=362880/2880
C=126
So there are 126 unique ways to pick 4 people from a group of 9 people.
Answer:
Step-by-step explanation:
<u>We know that:</u>
- Samantha = 15 + 2x
- Matt = 3 + 4x
- Samantha = Matt
- [x = Number of hours]
<u>Solution:</u>
- 15 + 2x = 3 + 4x
- => 15 - 3 = -2x + 4x
- => 12 = 2x
- => x = 6
Hence, after 6 hours of work, Samantha and Matt will have the same amount.
Angle 8 and Angle 3 are supplementary same side angles
Well you need to find a common denominator which 30 is the closest one. 5/6 becomes 25/30, 9/10 becomes 27/30. 27/30+ 25/30 = 52/30. To simplify that you divide by 2 to get 26/15. It is no longer divisible to a whole number after that point.
