The correct two-way frequency table for the data is <u>Men </u><u>and </u><u>Women </u><u>Leisure Time Activity Preferences.</u>
<h3>What is a correct two-way frequency table?</h3>
A correct two-way frequency table displays frequencies for two categories (rows and columns) collected from categorical variables (men and women).
Men and Women Leisure Time Activity Preferences;
Playing Sports Dancing Watching movies/TV Row totals
Men 11 3 6 20
Women 5 16 9 30
Column totals 16 19 15 50
Hence, the correct two-way frequency table for the data is Men and Women Leisure Time Activity Preferences.
To learn more about two-way frequency tables click the link given below.
brainly.com/question/4555163
Use Multiplication Distribute Property: (xy)^a = x^ay^a
6^2(x^-2)^2(0.5x)^4
Simplify 6^2 to 36
36(x^-2)^2(0.5x)^4
Use this rule: (x^a)^b = x^ab
36x^-4(0.5x)^4
Use the Negative Power Rule: x^-a = 1/x^a
36 × 1/x^4(0.5x)^4
Use the Multiplication Distributive Property: (xy)^a = x^ay^a
36 × 1/x^4 × 0.5^4x^4
Simplify 0.5^4 to 0.0625
36 × 1/x^4 × 0.0625x^4
Simplify
2.25x^4/x^4
Cancel x^4
<u>2.25</u>
Answer:
![\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B1.%5C%20f%5E%7B-1%7D%28x%29%3D4%5Clog%28x%5Csqrt%5B4%5D2%29%7D%5C%5C%5C%5C%5Cboxed%7B2.%5C%20f%5E%7B-1%7D%28x%29%3D%5Clog%28x%5E5%2B5%29%7D%5C%5C%5C%5C%5Cboxed%7B3.%5C%20f%5E%7B-1%7D%28x%29%3D%5Csqrt%7B4%5E%7Bx-1%7D%7D%7D)
Step-by-step explanation:


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![--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)](https://tex.z-dn.net/?f=--------------------------%5C%5C2.%5C%5Cy%3D%2810%5Ex-5%29%5E%5Cfrac%7B1%7D%7B5%7D%5C%5C%5C%5C%5Ctext%7BExchange%20x%20and%20y.%20Solve%20for%20y%3A%7D%5C%5C%5C%5C%2810%5Ey-5%29%5E%5Cfrac%7B1%7D%7B5%7D%3Dx%5Cqquad%5Ctext%7B5%20power%20of%20both%20sides%7D%5C%5C%5C%5C%5Cbigg%5B%2810%5Ey-5%29%5E%5Cfrac%7B1%7D%7B5%7D%5Cbigg%5D%5E5%3Dx%5E5%5Cqquad%5Ctext%7Buse%7D%5C%20%28a%5En%29%5Em%3Da%5E%7Bnm%7D%5C%5C%5C%5C%2810%5Ey-5%29%5E%7B%5Cfrac%7B1%7D%7B5%7D%5Ccdot5%7D%3Dx%5E5%5C%5C%5C%5C10%5Ey-5%3Dx%5E5%5Cqquad%5Ctext%7Badd%205%20to%20both%20sides%7D%5C%5C%5C%5C10%5Ey%3Dx%5E5%2B5%5Cqquad%5Clog%5C%20%5Ctext%7Bof%20both%20sides%7D%5C%5C%5C%5C%5Clog10%5Ey%3D%5Clog%28x%5E5%2B5%29%5CRightarrow%20y%3D%5Clog%28x%5E5%2B5%29)

<u>k / 9 = 12</u>
Multiply each side of the equation by 9 : <em>k = 108</em>
<u>84 n = 504</u>
Divide each side of the equation by 84 : <em>n = 6</em>
<u>6 = m / 148</u>
Multiply each side of the equation by 148 : <em>888 = m</em>