Question

What is an equation of the line that passes through the point (8,5) and (-6,5)

Answer 1

For this case we have that by definition, the equation of the line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have two points through which the line passes:

$(x_ {1}, y_ {1}) :( 8,5)\\(x_ {2}, y_ {2}): (- 6,5)$

We found the slope:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {5-5} {- 6-8} = \frac {0} {- 14} = 0$

The slope is zero.

Thus, the equation is of the form:

$y = b$

We substitute one of the points and find b:

$(x, y) :( 8,5)\\5 = b\\b = 5$

Finally, the equation is:

$y = 5$

Answer:

$y = 5$