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taurus [48]
3 years ago
4

Why do scientists use models of natural systems? A) Scientists use models of natural systems because these systems are often too

large, too small, or too complex to study directly B) Scientists use models of natural systems because they like to use art in science C) Scientists use models of natural systems because the models are more accurate than the actual system D) Scientists use models of natural systems because models work exactly the way these systems do in nature Elimi
Social Studies
1 answer:
Vladimir79 [104]3 years ago
8 0

Answer:

A) Scientists use models of natural systems because these systems are often too large, too small, or too complex to study directly

Explanation:

Natural systems are those that were not created by humans (non-artificial ones), ie of non-human origin (natural). They are natural systems: The solar system, Biosphere, Ecosystem. Set of elements that interact with each other, making exchanges and influencing each other. These systems are huge, or too smal, with many different components, complex and difficult to evaluate, so when scientists want to study this type of system, it is necessary to make models that represent the system as faithfully as possible.

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The Fundamental Rights of India are based on the ____________________________ which was adopted by the United Nations in 1948
Anarel [89]

Answer:

The Rights have their origins in many sources, including England's Bill of Rights, the United States Bill of Rights and France's Declaration of the Rights of Man. There are six fundamental rights recognised by the Indian constitution: Right to equality (Articles. 14-18)

Explanation:

Options confusing but here what I got

8 0
3 years ago
Money committed to something that is expected to produce a financial profit is a(n) __________.
Diano4ka-milaya [45]

Answer:

b investment

Explanation:

7 0
3 years ago
Read 2 more answers
Assume that the rod in Fig.31.2 has a length of 0.86 m,the resistor has value 2.2 ,and a magnetic field of 8.0 T is directed int
frutty [35]

1) 0.48 m/s

2) Clockwise

3) 10.3 N

Explanation:

1)

The figure is missing: find it in attachment.

As the rod is pulled along the rails, in the region of magnetic field, an electromotive force is induced in the rod itself, due to the change in magnetic flux through the circuit enclosed by the rod and the rails.

The magnitude of this induced electromotive force (which is equivalent to the potential difference induced in the rod) is

V=BvL

where:

B is the strength of the magnetic field

v is the speed of the rod

L is the length of the rod

Also we know that according to Ohm's law, the potential difference across the resistance is equal to

V=RI

where

R is the resistance of the rod

I is the current

Since the potential difference across the resistor is equal to the potential difference across the rod, we can combine the two equations, and we get:

BvL=RI\\v=\frac{RI}{BL}

Here we have:

R=2.2 \Omega\\B=8.0 T\\L=0.86 m\\I=1.5 A

Therefore, the speed of the rod must be:

v=\frac{(2.2)(1.5)}{(8.0)(0.86)}=0.48 m/s

2)

Here we have to apply Lenz's law, which states that the direction of the induced emf (and so, of the induced current) is such that it opposes the change in magnetic flux through the system.

First of all, here we notice that as the rod moves, the area enclosed by the circuit decreases: this means that the magnetic flux through the circuit decreases too.

As a result, the induced current must produce a magnetic field which goes in the same direction as the external field, in order to "restore" the magnetic flux. Here the external magnetic field points inside the paper, so the magnetic field produced by the induced current must also point inside the paper.

In order for that to happen, we see that the induced current must flow clockwise: in fact, if we take the rod and we apply the right-hand rule, we see that if we place the thumb towards the left (direction of the clockwise current), the other fingers "wrapped" point into the paper at the center of the circuit, so this is the correct direction.

3)

A current-carrying wire in a magnetic field experiences a force of magnitude

F=ILB

where

I is the current

L is the length of the wire

B is the strength of the magnetic field

Here we have

I = 1.5 A

L = 0.86 m

B = 8.0 T

So the force experienced by the rod is

F=(1.5)(8.0)(0.86)=10.3 N

Therefore, we must apply an equal and opposite force of 10.3 N in order to maintain keep the acceleration of the rod to zero, so that the velocity is constant, and the current is constant as well.

7 0
3 years ago
What does adapt mean in social studies
kodGreya [7K]
To be <span>become adjusted to new conditions.</span>
3 0
3 years ago
If Vm were clamped at -40 mV, what would the driving force be for Na+ to cross the cell membrane? What would be the driving forc
Helga [31]

Answer:

-35 mV and +56 mV

Explanation:

The membrane potential is the energy that is needed to drive membrane changes across the phospholipid bi-layer membrane.

Ions can move in and out of the cell through protein channels. The movement of the ions is as a result of concentration that affect the operation of ion gates.

The reverse potential is given by the Nernst equation:

E_{ion} = \frac{RT}{zF} ln\frac{ion_{outside} }{ion_{inside} }

where, R = gas constant

            T = temperature (Kelvin)

             z = ion charge

             F = Faraday's charge

The potential is calculated and the result is -35 mV and +56 mV respectively.

4 0
3 years ago
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