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kkurt [141]
3 years ago
6

During a recent rainstorm, 8 88 centimeters of rain fell in Dubaku's hometown, and 2.36 2.362, point, 36 centimeters of rain fel

l in Elliot's hometown. During the same storm, 15.19 15.1915, point, 19 centimeters of snow fell in Alperen's hometown.
Mathematics
1 answer:
ehidna [41]3 years ago
4 0

Question is Incomplete; Complete question is given below;

During a recent rainstorm, 8 centimeters of rain fell in Dubaku's hometown, and 2.36 centimeters of rain fell in Elliot's hometown. During the same storm, 15.19 centimeters of snow fell in Alperen's hometown. How much more rain fell in Dubaku's town than in Elliot's town?

Answer:

The rain fell 5.64 cm more in Dubaku's town than in Elliot's town.

Step-by-step explanation:

Given:

rain fell in Dubaku's hometown = 8 cm

rain fell in Elliot's hometown = 2.36 cm

snow fell in Alperen's hometown = 15.19cm

We need to find how much more rain fell in Dubaku's town than in Elliot's town.

Solution:

Now we can say that;

to find how much more rain fell in Dubaku's town than in Elliot's town we will subtract rain fell in Elliot's hometown from rain fell in Dubaku's hometown.

framing in equation form we get;

Amount of rain fell more in  Dubaku's town than in Elliot's town = 8-2.36 = 5.64\ cm

Hence The rain fell 5.64 cm more in Dubaku's town than in Elliot's town.

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Answer:

Problem 1 : After 0.25 s

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Step-by-step explanation:

Problem 1

This is a standard physics problem

The equation that defines the movement of the grasshopper given the initial velocity, and the acceleration is the following

Distance =  Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 0, because the grasshopper is on the ground and we choose the reference system there)

Vo is the initial velocity = 8 feet/sec

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 = - 32.174 feet per second per second.)

t is the time

We substitute in the equation, and solve for t (time)

Distance =  Do + Vo*t + 0.5*a*t^2

(1 foot)=  (0)+ (8 feet/s)*t + 0.5*(-32.174 feet/s^2)*t^2

Solving this equation, we get that

t = 0.25 s

Problem 2

This problem is similar to the previous one

We apply the same formula

D =  Do + Vo*t + 0.5*a*t^2

But in this case, we are going in the opposite direction, and we have an initial distance.

Do = 27 feet

Vo is the initial velocity of the nut = -6 feet/s

D = 0  (Ground)

We substitute in the equation, and solve for t (time)

(0) =  (27) + (-6 feet/s)*t + 0.5*(-32 feet/s^2)*t^2

t = 1.125 s  <  2s

The nut reaches ground in 1.125 s, so the squirrel doesn't reach the ground before the nut

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4 years ago
How do u do find vertices of dilation if the factor is k =3
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Do you have a graph or a picture? It would be easier to explain
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15 x sin(30)=?/15 x 15
Delicious77 [7]

Answer:

The exact value of

sin

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30

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sin(30) is

1

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⋅

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The result can be shown in multiple forms.

Exact Form:

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Decimal Form:

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Mixed Number Form:

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Step-by-step explanation:

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