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Doss [256]
2 years ago
15

Evaluate the logarithm log6 1296

Mathematics
1 answer:
Phantasy [73]2 years ago
3 0

Answer:

What?...

Step-by-step explanation:

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Dont get it at all....
harina [27]
Hope this helps :) I would type it out but i couldn't show what degrees go where.. If you need it step by step i can help<span />

5 0
3 years ago
What is the next number in the sequence?
charle [14.2K]
Looks like the next term in the sequence is generated by multiplying the previous term by 3 and adding 1:

1\times3+1=4
4\times3+1=13
13\times3+1=40
40\times3+1=121

If the pattern holds, the next term is probably going to be

121\times3+1=364
8 0
3 years ago
How can you tell if an element has been oxidized?
Rus_ich [418]

Step-by-step explanation:

B. Its oxidation state is higher in the product than in the reactant

4 0
3 years ago
PLs HELPPpppPPPppppPPp
UNO [17]

Answer:

I could tell you that the fist second and third would be <u><</u> > <u><</u>

Step-by-step explanation:

6 0
3 years ago
How to divide (x^2+5x-36)÷(x-4)
mr_godi [17]

Answer:

x + 9

Step-by-step explanation:

Since the divisor is in the form of <em>x - c</em>, use what is called <em>Synthetic Division</em>. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

4| 1 5 -36

↓ 4 36

----------------

1 9 0 → x + 9

You start by placing the c in the top left corner, then list all the coefficients of your dividend [x² + 5x - 36]. You bring down the original term closest to <em>c</em><em>,</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have NO REMAINDER. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x, and the 9 follows right behind it, giving you the other factor of x + 9.

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

4 0
3 years ago
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