Step-by-step explanation:
The question is wrong. The correct equation is :

We know that the equation gives the relation between temperature readings in Celsius and Fahrenheit.
Therefore, giving that we know the value in Fahrenheit ''F'' we can find the reading in Celsius ''C''. This define a function C(F) that depends of the variable ''F''.
So for the incise (a) we answer Yes, C is a function of F.
For (b) we need to find the mathematical domain of this function. Giving that we haven't got any mathematical restriction, the mathematical domain of the function are all real numbers.
Dom (C) = ( - ∞ , + ∞)
For (c) we know that the water in liquid state and at normal atmospheric pressure exists between 0 and 100 Celsius.
Therefore the range will be
Rang (C) = (0,100)
Now, we need to find the domain for this range. We do this by equaliting and finding the value for the variable ''F'' :
For C = 0 :
⇒ 
And for C = 100 :
⇒ 
Therefore, the domain as relating temperatures of water in its liquid state is
Dom (C) = (32,212)
For (d) we only need to replace in the equation by
and find the value of C ⇒
⇒

≅ 21.67
C(71) = 21.67 °C
Answer:

Step-by-step explanation:
The tunnel, the ground and the depth of the tunnel form a right angle triangle.
The length of the tunnel is the hypotenuse of the right triangle that has been formed.
Let the length of the tunnel be
.
Using the sine ratio, we obtain;

The length of the opposite side is 
We substitute the given values to obtain;


We cross multiply to obtain;


Therefore the correct answer is C.
Answer:
Number 2 is 3:4.
Number 1 is d.
Step-by-step explanation:
Boxers and collies added together gives you 12:16. Divide them both by 4 and you get 3:4.
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The number of student in class 4 (6) divided by the total number of kids in the entire class (18) gives you 0.33333333333. Multiply that by 100 and it gives you 33.3333333333. As a percentage it is 33 1/2 %
Answer:
a) 0.2 L
b) 4800 ml
c) 2400 ml
Step-by-step explanation:
Total volume of water = 5 litres
Since 1000 milliliters make 1 L
5L = 5000 ml
a) litres of water spilt = 200/1000 = 0.2 L
b) milliliters of water remaining = 5000 - 200 = 4800 ml
c) since it was expressly stated in the question that the remaining water was divided evenly; 4800/2 = 2400 ml in each bowl