Answer:
They are, because similarity means that the ratio of the sides are equal and they are proportionate.
Step-by-step explanation:
If you look at the graph, you can count 2 units from the smaller diamond/rhombus to the other diamond/rhombus. If you count the amount of units on each side, you will find that they are not equal, however they should be proportional if you calculate the angles of 90°.
Answer:
sin t =
cos t =
tan t = 
csc t =
sec t =
cot t =
Step-by-step explanation:
In the unit circle:
- x-coordinate of a point on the circle represents cosine the angle between the + ve part of x-axis and the terminal side which joins the center of the circle and this point
- y-coordinate of a point on the circle represents sine the angle between + ve part of x-axis and the terminal side which joins the center of the circle and this point
In the attached figure
∵ t represents the angle between + ve part of x-axis
and the terminal side drawn from the center of the circle to
point P
∴ The coordinates of point P are (cos t , sin t)
∵ The coordinates of P are (
,
)
∴ sin t =
∴ cos t =
∵ tan t = 
- Substitute the values of sin t and cos t
∴ tan t =
- Multiply up and down by 5 to simplify the fraction
∴ tan t = 
∵ csc t = 
- Reciprocal the value of sin t
∴ csc t =
∵ sec t = 
- Reciprocal the value of cos t
∴ sec t =
∵ cot t = 
- Reciprocal the value of tan t
∴ cot t =
Answer:
If you choose any value for k other than 6, that will be give you the one solution.
If k=6, you have no solutions because the lines will be parallel.
Step-by-step explanation:
We are going to put each of this in y=mx+b where m is the slope and b is the y-intercept.
kx+2y=5
Subtract kx on both sides:
2y=-kx+5
Divide both sides by 2:
y=(-k/2)x+(5/2)
The slope is -k/2 and the y-intercept is 5/2
3x+y=1
Subtract 3x on both sides:
y=-3x+1
The slope is -3 and the y-intercept is 1.
We want the system to have one solution so we want the slopes to be difference.
So we don't want (-k/2)=(-3).
Multiply both sides by -2: k=6.
We won't want k to be 6.
Answer:
6 lunch tables
Step-by-step explanation:
Since one lunch table can hold 10 students and 60 students are needed to hold,
60 ÷ 10 = 6 lunch tables