Photo? i cannot answer without a photo:)
Answer:
a= 6
b = 7
c = 8
d = 7
e = 6
Step-by-step explanation:
Notice that the bike is 6 feet above the ground to start with, so when it starts rolling, the green dot is exactly 6 feet from the ground, which gives a=6
when the distance covered by the bike is 
, (see first red dot in the attached image), the position of the green dot is exactly 1 foot added to 6 ft= 7 feet
so b = 7
when the distance covered is 
, now the green dot would be at the top of the wheel (second red dot in the attached image) which involves adding 2 feet to the original 6 feet. That is: c = 8
when the distance covered is 
, the green dot is at the position of the third red dot in the attached image., that it exactly one foot added to 6 feet = 7 ft which gives the value of d = 7
and finally, when the distance covered is 
. the green dot has completed a full circle and is now again in its lower position (nothing - zero) added to 6 feet = 6ft, giving e = 6.
<u>Answer:</u>
y=-1/4x-1
<u>How to find the </u><u>slope</u>
To find the slope of the line you need to do the change in y/change in x. This is also known as the rise/run. To do this you count the spaces in between the two points.
In this graph the change in y (rise) is 2. The change in x (run) is 8. Since the line is going down they are negative. The rise/run is -2/8. This can be simplified to -1/4.
Slope: -1/4x
<u>How to find the y-intercept</u>
To find the y-intercept, you need to look at where the line crosses y.
In this graph the line crosses y at -1.
Y-intercept: -1
<u>Final</u><u> </u><u>equation</u><u>:</u><u> </u><u>-</u><u>1</u><u>/</u><u>4x-1</u>
Answer:21
Step-by-step explanation:
One = <AOB
two= <BOC
three = <COD
four = <DOE
five = <EOF
six = <AOC
Seven = <AOD
Eight = <AOE
Nine = <BOD
Ten = < BOE
Eleven = < BOF
Theres a bunch more but im not listing them
Answer:
135 square feet
Step-by-step explanation:
area of base and top=2(1/2×6×2.5)=15 square feet.
area of three faces=(2.5+6+6.5)×8=15×8=120 ft
total surface area=15+120=135 square feet.
