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4 years ago

Plz help me asap plzzzzz..

Mathematics

1 answer:

Gre4nikov [31]4 years ago

6 0

28:

1*28 = 28

2*14 = 28

4*7 = 28

Factors of 28 are 1, 2, 4, 7, 14, 28.

15:

1*15 = 15

3*5 = 15

Factors of 15 are 1, 3, 5, 15.

36:

1*36 = 36

2*18 = 36

3*12 = 36

4*9 = 36

6*6 = 36

Factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36

29:

1*29 = 29

Factors of 29 are 1, 29.

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Question 12

WARRIOR [948]

Answer:

Mark's mass is 26 kg.

Step-by-step explanation:

Average mass of Jeremy, Mark and Zack = 28kg

Average mass of Jeremy and Zack = 29 kg

Let,

Jeremy's mass = x

Mark's mass = y

Zack's mass = z

Average of three of them = $\frac{Jeremy's mass + Mark's + Zack's}{3}$

28 = $\frac{x+y+z}{3}\\$

$28*3 = x+y+z\\84 = x+y+z$

x+y+z = 84 Eqn 1

$29 =\frac{x+z}{2}\\58=x+z\\$

x+z = 58 Eqn 2

Now putting value of x+z from Eqn 2 in Eqn 1

x + z + y = 84

58 + y = 84

y = 84 - 58

y = 26

Thereofore,

Mark's mass is 26 kg.

6 0

3 years ago

The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown.

lakkis [162]

The smallest perimeter is 72.44 inches. The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown. As much as possible, the sum of the length of the two remaining side must be greater than the other side. Given the side is 30, then the sum of the two remaining sides should be greater than 30 inches.

7 0

3 years ago

Slope is 1/2 and (4,6) is on the line

AleksandrR [38]

Answer:

y-6=1/2(x-4)

Step-by-step explanation:

y-y1=m(x-x1)

y-6=1/2(x-4)

6 0

3 years ago

Read 2 more answers

Which property justifies this statement?

bonufazy [111]

Addition property of equality

6 0

3 years ago

Read 2 more answers

Complete the data table for the function f(x) = -x - 2 + 2.

alexgriva [62]

Given the following function:

$\text{ f(x) = }\sqrt[]{-x\text{ -2}}\text{ + 2}$

y = f(x)

Therefore, let's complete the data table by substituting each x-values to be able to get the respective y-values,

We get,

At x = -2,

$\text{ y = f(x) = }\sqrt[]{-x-2}\text{ + 2}$ $\text{f(-2) = }\sqrt[]{-(-2)-2}\text{ + 2}$ $\text{ = }\sqrt[]{2\text{ - 2}}\text{ + 2}$ $\text{ = }\sqrt[]{0}\text{ + 2}$ $\text{ y = f(-2) = 2}$

Therefore, y = 2 at x = -2.

At x = -3,

$\text{ y = f(x) = }\sqrt[]{-x-2}\text{ + 2}$ $\text{f(-3) = }\sqrt[]{-(-3)-2}\text{ + 2}$ $\text{= }\sqrt[]{3-2}\text{ + 2}$ $\text{= }\sqrt[]{1}\text{ + 2}$ $\text{= }1\text{ + 2}$ $\text{ f(-3) = 3}$

Therefore, y = 3 at x = -3.

At x = -6,

8 0

1 year ago