400150000 is the answer pal
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Okay so whats the question?
Answer:
Step-by-step explanation:
given that the following data represent the discrete probability distribution for the number of stars that reviewers have a first edition statistics reference book.
Stars 5 4 3 2 1
Probability 25% 35% 20% 10% 10%
H0: Second edition is as per the above probabilities
Ha: atleast one is different from the above probability
(two tailed chi square test)
Alpha = 0.025
Assuming H0 to be true we calculate expected frequencies for total 80
chi square calculatons are shown below
df = 4
5 4 3 2 1 Total
Observed 28 28 13 6 5 80
Expected 20 28 16 8 8 80
chi square
(O_E)^2/E 3.2 0 0.5625 0.5 1.125 5.3875
p value =0.1455
Since p value >0.025, we accept H0
The expected requency of three-star reviews is ________.16
So this translates to:
5e + 5n = 25.95
2e + 6n = 22.38
One way to solve that is to multiply the top equation by 2, and the bottom equation by 5:
10e + 10n = 51.90
10e + 30n = 111.90
Then subtract the top from the bottom to get:
20n = 60
and divide by 20 to get
n = 3
So you know that note paper costs $3. Substituting that into the top equation you get:
5e + 5*3 = 25.95 or
5e + 15 = 25.95
Subtracting 15 from both sides you get:
5e = 10.95
Dividing by 5 you get:
e = $2.19
Step-by-step explanation:
right now but I have no idea how much that would have to be in the same place as last week and he said it would be a lot of people are coming to see you and the girls are doing well and