This is an exponential equation. We will solve in the following way. I do not have special symbols, functions and factors, so I work in this way
2 on (2x) - 5 2 on x + 4=0 =>. (2 on x)2 - 5 2 on x + 4=0 We will replace expression ( 2 on x) with variable t => 2 on x=t =. t2-5t+4=0 => This is quadratic equation and I solve this in the folowing way => t2-4t-t+4=0 => t(t-4) - (t-4)=0 => (t-4) (t-1)=0 => we conclude t-4=0 or t-1=0 => t'=4 and t"=1 now we will return t' => 2 on x' = 4 => 2 on x' = 2 on 2 => x'=2 we do the same with t" => 2 on x" = 1 => 2 on x' = 2 on 0 => x" = 0 ( we know that every number on 0 gives 1). Check 1: 2 on (2*2)-5*2 on 2 +4=0 => 2 on 4 - 5 * 4+4=0 => 16-20+4=0 =. 0=0 Identity proving solution.
Check 2: 2 on (2*0) - 5* 2 on 0 + 4=0 => 2 on 0 - 5 * 1 + 4=0 =>
1-5+4=0 => 0=0 Identity provin solution.
Answer: You must see if it is a distributive property of multiplication over addition or a distributive property of multiplication over subtration.
Step-by-step explanation:
You can find two kind of expressions in this property:
- Distributive property of multiplication over addition: When you mulitply a sum by a number. For example:
- Distributive property of multiplication over subtration: When you mulitply a subtration expression by a number. For example:

To factor you have to do this:
s^2 + 9s = -20
+ 20 +20
s^2 + 9s + 20 = 0
now you need to numbers that multiplied give you 20
and then those same 2 numbers have to add to 9
5 x 4 = 20
5+ 4 = 9
(x + 4) (x+ 5)
that means that x= -4, and -5
The answer is C because it’s the only answer that could be correct.
Answer:
B
Step-by-step explanation:
<u>Definition:</u> Two rectangles are similar when they have corresponding sides proportional are proportional by dilation.
For example, rectangles with sides 3 cm, 4cm and 6 cm, 8 cm are similar, but rectangles with sides 3 cm, 4 cm and 6 cm, 10 cm are nor similar.
Since all angles in rectangle are always right angles, then options A and C are false (in terms of your question).
Option D is false too, because translation doesn't change the length, and in this case two rectangles are congruent.
Option B is true according to definition.