Jeff bought 1.5 pounds of pork.
1 pound of pork = 3.64
0.5 pounds of pork = 1.82 (divided 3.64 by 2 to find 0.5 pounds of pork)
3.64 + 1.82 = 5.46
Jeff also bought 2.5 pounds each of beer and chicken.
1 pound of beef = 5.99
2 pounds of beef = 11.98
0.5 pounds of beef = 2.995 (5.99 divided by 2)
11.98 + 2.995 = 14.975
1 pound of chicken = 4.79
2 pounds of chicken = 9.58
0.5 pounds of chicken = 2.395
9.58 + 2.395 = 11.975
Add up the total amount of the 1.5 pounds of pork and 2.5 pounds each of beef and chicken.
5.46 + 14.975 + 11.975 = $32.41
Product means multiply
d is the variable, the depth of the river
so product of 86 and depth is 86 times d or 86*d
A.) 18 m
lets say u star at point A (0m from the start) it then moves to point B (20m from the start (20x1=20)) then it moves to point C (2m back from B making it 18m from A (.5x4=2))
Answer:
Dimensions of printed area
w = 8.95 cm
h = 13.44 cm
A(max) = 120.28 cm²
Step-by-step explanation:
Lets call " x " and "y" dimensions of the poster area ( wide and height respectively) . Then
A(t) = 180 cm² = x*y y = 180/ x
And the dimensions of printed area is
A(p) = ( x - 2 ) * ( y - 3 ) then as y = 180/x we make A function of x only so
A(x) = ( x - 2 ) * ( 180/x - 3 ) ⇒ A(x) = 180 - 3x - 360/x +6
A(x) = - 3x - 360 /x + 186
Taking derivatives on both sides of the equation we get:
A´(x) = -3 + 360/ x²
A´(x) = 0 -3 + 360/ x² = 0 -3x² + 360 = 0
x² = 120 ⇒ x = √120 x = 10.95 cm
And y = 180 / 10.95 ⇒ y = 16.44 cm
Then x and y are the dimensions of the poster then according to problem statement
w of printed area is x - 2 = 10.95 - 2 = 8.95 cm
and h of printed area is y - 3 = 16.44 - 3 = 13.44 cm
And the largest printed area is w * h = ( 8.95)*(13.44)
A(max) = 120.28 cm²