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sveta [45]
3 years ago
9

Brandy is trying to factor the quadratic $3x^2 - x - 10.$ She starts by assuming that the quadratic factors as \[3x^2 - x - 10 =

(x + B)(3x + D),\]for some integers $B$ and $D.$ After some work, Brandy successfully factors the quadratic. Find the ordered pair $(B,D).$
Mathematics
1 answer:
taurus [48]3 years ago
7 0

Answer:

(B , D) = (-2,5)

Step-by-step explanation:

The given quadratic expression is

3x^{2} -x-10

compare the given expression with ax^{2} +bx+c

so we have a = 3 , b = -1 ,c = -10

now ac=3 (-10)=- 30 and b= -1

we need to find two numbers such that their product is -30 and sum is -1

-6 and 5 are such numbers

so we have

3x^{2} -6x+5x-10

grouping first two terms and last two terms

(3x^{2} -6x)+(5x-10)

factor out 3x from first two terms and 5 from last two terms

3x(x-2) +5(x-2)          

(x-2)(3x+5)        ( factor out (x-2))

(x+(-2))(3x+5)

hence B =-2 and D= 5

(B,D)= (-2,5)

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