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malfutka [58]
3 years ago
14

The amount of time that customers wait in line during peak hours at one bank is normally distributed with a mean of 13 minutes a

nd a standard deviation of 3 minutes. The percentage of time that the waiting time lies between 11 and 13 minutes is equal to the area under the standard normal curve between ___and ___.
a).62, .77
b) -.67,0
c)-2, 0
d) 0, .67
Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer: I believe the answer is c)-2, 0

Step-by-step explanation: The amount of time that customers wait in line during peak hours at one bank is normally distributed with a mean of 13 minutes and a standard deviation of 3 minutes then the answer should be c)-2, 0 ?

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kolbaska11 [484]

Answer:

Step-by-step explanation:

16x^4y^-3z^4 / 36x^-2yz^0

16x^4y^-3z^4 = 16x^4z^4/y^3

36x^-2yz^0 = 36x^-2y(1) =36x^-2y = 36y/x^2

16x^4y^-3z^4 / 36x^-2yz^0

= (16x^4z^4/y^3) / (36y/x^2)

= 16x^4z^4/y^3 * x^2/36y  

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or another way

fist multiply it out

f(x) = 4x^(3/5) - x^(8/5)

now differentiate knowing d/dx(x^n) = n x^(n-1)

to get

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simplify to get

12/5/x^(2/5) -   8/5 x^(3/5)

If this is what your looking for please give me brainiest, i have done this problem in the past so i know how to solve it :)

5 0
3 years ago
CHECK MY ANSWER??
Tatiana [17]
You are partially correct :) 2^SQR(10) x SQR(10) = 20 
The answer is just 20
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is the question multiple choice? if not I'd go with absolute value


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4 years ago
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