We have the following expression:
y = logbx
We clear x of the expression.
We have then:
b ^ y = b ^ (logbx)
Rewriting:
x = b ^ y
Substituting we have:
x = b ^ 0
x = 1
Answer:
If (x, 0) lies on the graph of y = logbx, then:
x = 1
Answer:
4
Step-by-step explanation:
b+12 =16
-12. -12
b = 4
hope this helps
Going to answer this in the comments because my keyboard is covering my screen :(