Answer:
a) Attached
b) P=0.60
c) P=0.80
d) The expected flight time is E(t)=122.5
Step-by-step explanation:
The distribution is uniform between 1 hour and 50 minutes (110 min) and 135 min.
The height of the probability function will be:

Then the probability distribution can be defined as:
![f(t)=\frac{1}{25}=0.04 \,\,\,\,\\\\t\in[110,135]](https://tex.z-dn.net/?f=f%28t%29%3D%5Cfrac%7B1%7D%7B25%7D%3D0.04%20%5C%2C%5C%2C%5C%2C%5C%2C%5C%5C%5C%5Ct%5Cin%5B110%2C135%5D)
b) No more than 5 minutes late means the flight time is 125 or less.
The probability of having a flight time of 125 or less is P=0.60:

c) More than 10 minutes late means 130 minutes or more
The probability of having a flight time of 130 or more is P=0.80:

d) The expected flight time is E(t)=122.5

You need to isolate x.
71 - 5x = 9x - 13
Add 13 to both sides.
84 - 5x = 9x
Add 5x to both sides.
84 = 14x
Divide both sides by 14.
6 = x
<h3>The answer is x = 6.</h3>
Answer:
by substituting the values we get
51÷(15+2)
51÷17=3
hope it helps you mate
please mark me as brainliast
Only <span>set Y = {6, 24, 36, 78, 84}, contains only whole numbers divisible by 6.
There were no options but this was the answer to this question on a quiz.
hope this helps!</span>