Answer:
600
Step-by-step explanation:
you can do 3x2 witch is 6 then add the two zeros
For this case we have the following expression:
![(4m + 3) + 5m =](https://tex.z-dn.net/?f=%284m%20%2B%203%29%20%2B%205m%20%3D)
We eliminate the parentheses:
![4m + 3 + 5m =](https://tex.z-dn.net/?f=4m%20%2B%203%20%2B%205m%20%3D)
We add similar terms:
![4m + 5m + 3 =\\9m + 3](https://tex.z-dn.net/?f=4m%20%2B%205m%20%2B%203%20%3D%5C%5C9m%20%2B%203)
Thus, we have a linear expression (the exponent of the variable term is 1).
The expression consists of two algebraic terms, so it is a binomial.
We have that algebraic terms are integers when they have no literal denominator.
9m: Positive, whole, rational term.
3: Constant term.
Answer:
9m: Positive, whole, rational term.
3: Constant term.
We know, Volume of a Cone = πr² h/3
v = 3.14 * (11)² * 4.5/3
v = 3.14 * 121 * 1.5
v = 569.91 in³
In short, Your Answer would be Option C
Hope this helps!
Answer:
w<10
number - A
(<) means "open circle to the left."
Answer:
C.5
Step-by-step explanation:
Fiona:
After t trials, she would have:
![f(t) = 4.127(1.468)^t](https://tex.z-dn.net/?f=f%28t%29%20%3D%204.127%281.468%29%5Et)
Karl:
After t trials, he would have:
![k(t) = 0.897(1.992)^t](https://tex.z-dn.net/?f=k%28t%29%20%3D%200.897%281.992%29%5Et)
At what number of trials would Fiona and Karl have the same number of beans?
This is t for which:
![f(t) = k(t)](https://tex.z-dn.net/?f=f%28t%29%20%3D%20k%28t%29)
So
![4.127(1.468)^t = 0.897(1.992)^t](https://tex.z-dn.net/?f=4.127%281.468%29%5Et%20%3D%200.897%281.992%29%5Et)
![0.897(1.992)^t = 4.127(1.468)^t](https://tex.z-dn.net/?f=0.897%281.992%29%5Et%20%3D%204.127%281.468%29%5Et)
![\frac{(1.992)^t}{(1.468)^t} = \frac{4.127}{0.897}](https://tex.z-dn.net/?f=%5Cfrac%7B%281.992%29%5Et%7D%7B%281.468%29%5Et%7D%20%3D%20%5Cfrac%7B4.127%7D%7B0.897%7D)
![(\frac{1.992}{1.468})^t = 4.6](https://tex.z-dn.net/?f=%28%5Cfrac%7B1.992%7D%7B1.468%7D%29%5Et%20%3D%204.6)
![(1.35695)^t = 4.6](https://tex.z-dn.net/?f=%281.35695%29%5Et%20%3D%204.6)
![\log{(1.35695)^t} = \log{4.6}](https://tex.z-dn.net/?f=%5Clog%7B%281.35695%29%5Et%7D%20%3D%20%5Clog%7B4.6%7D)
![t\log{1.35695} = \log{4.6}](https://tex.z-dn.net/?f=t%5Clog%7B1.35695%7D%20%3D%20%5Clog%7B4.6%7D)
![t = \frac{\log{4.6}}{\log{1.35695}}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B%5Clog%7B4.6%7D%7D%7B%5Clog%7B1.35695%7D%7D)
![t = 5](https://tex.z-dn.net/?f=t%20%3D%205)
So the correct answer is 5 trials, option C.