Positively charged protons in the nucleus, hope this helps.
Answer:
The answer is "208 mL".
Explanation:
In dilutions of different concentration, its initial volume for glucose solution V1 can be obtained by using the following formula, i.e.
The solution of 520 mL final glucose solution thus requires 208 mL of glucose solution of .
Ammonia gas will have a mass of 3.17grams.
HOW TO CALCULATE MASS:
- The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass.
- However, to calculate the number of moles present in the ammonia gas given in this question, we use the formula as follows:
where;
- P = pressure (atm)
- V = volume (L)
- n = number of moles (mol)
- R = gas law constant
- T = temperature
n = PV ÷ RT
n = (1.2 × 3.7) ÷ (0.0821 × 290)
n = 4.44 ÷ 23.81
n = 0.186mol
- Mass of ammonia gas = 3.17g
- Therefore, the mass of ammonia gas is 3.17grams.
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