1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
attashe74 [19]
3 years ago
9

When positively charged particles were radiated onto a gold atom, a few of the particles bounced back. Which of the following ca

used this? Positively charged protons in the nucleus of the gold atom Positively charged electrons in the nucleus of the gold atom Negatively charged protons around the nucleus of the gold atom Negatively charged electrons around the nucleus of the gold atom
Chemistry
2 answers:
MariettaO [177]3 years ago
8 0
Positively charged protons in the nucleus, hope this helps.
Olin [163]3 years ago
3 0

Answer is: Positively charged protons in the nucleus of the gold atom.

This was famous Rutherford's Gold Foil Experiment: he bombarded thin foil of gold with positive alpha particles (helium atom particles, consist of two protons and two neutrons).  

Rutherford observed the deflection of alpha particles on the photographic film and notice that most of alpha particles passed straight through foil.

Rutherford theorized that atoms have their charge concentrated in a very small nucleus.

You might be interested in
Which of the following describes the arrangement of valence electrons in a bond between H and F?
Sloan [31]
C; The Valence electrons spend more time around the atom of F
6 0
2 years ago
Student carries out a titration to determine the concentration of a solution of
Nimfa-mama [501]

The concentration of the Nitric acid solution : 0.114 M

<h3>Further explanation  </h3>

Titration is a procedure for determining the concentration of a solution (analyte) by reacting with another solution whose known concentration (usually a standard solution) is called the titrant. Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range  

Titrations can be acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases  

Reaction

HNO₃ + NaOH → NaNO₃ + H₂O​

Concentration a standard solution  of sodium hydroxide :  0.0998 mol/dm³ , and the volume = 25 cm³

moles NaOH=

\tt mol=M\times V\\\\mol=0.0998\times 25\\\\mol=2.495~mlmoles

<em>From the equation, mol ratio HNO₃ : NaOH = 1 : 1, so mol HNO₃ = mol NaOH=</em><em>2.495 mlmoles</em>

<em></em>

The volume of HNO₃ = 21.8 cm³, so the concentration :

\tt M=\dfrac{n}{V}\\\\M=\dfrac{2.495}{21.8}\\\\M=0.114

7 0
2 years ago
what volume of a 0.149 m potassium hydroxide solution is required to neutralize 17.0 ml of a 0.112 m hydrobromic acid solution?
IgorLugansk [536]

Answer: 12.78ml

Explanation:

Given that:

Volume of KOH Vb = ?

Concentration of KOH Cb = 0.149 m

Volume of HBr Va = 17.0 ml

Concentration of HBr Ca = 0.112 m

The equation is as follows

HBr(aq) + KOH(aq) --> KBr(aq) + H2O(l)

and the mole ratio of HBr to KOH is 1:1 (Na, Number of moles of HBr is 1; while Nb, number of moles of KOH is 1)

Then, to get the volume of a 0.149 m potassium hydroxide solution Vb, apply the formula (Ca x Va)/(Cb x Vb) = Na/Nb

(0.112 x 17.0)/(0.149 x Vb) = 1/1

(1.904)/(0.149Vb) = 1/1

cross multiply

1.904 x 1 = 0.149Vb x 1

1.904 = 0.149Vb

divide both sides by 0.149

1.904/0.149 = 0.149Vb/0.149

12.78ml = Vb

Thus, 12.78 ml of potassium hydroxide solution is required.

5 0
2 years ago
How many formula units are in 239.2g of <br> Br2<br> MgCl2<br> H2O<br> Fe
Oksana_A [137]

The formula units in the substances are as follows:

  • Br2 = 8.99 × 10^23 formula units
  • MgCl2 = 1.51 × 10^24 formula units
  • H2O = 2.57 × 10^24 formula units
  • Fe = 2.57 × 10^24 formula units

<h3>How many moles are in 239.2 g of the given substances?</h3>

The moles of the substances are determined from their molar mass.

Molar mass of the substances is given as follows:

  • Br2 = 160 g/mol
  • MgCl2 = 95 g/mol
  • H2O = 18 g/mol
  • Fe = 56 g/mol

Formula units = mass/molar mass × 6.02 × 10^23

The formula units in the substances are as follows:

  • Br2 = 239.2/160 × 6.02 × 10^23 = 8.99 × 10^23 formula units
  • MgCl2 = 239.2/95 × 6.02 × 10^23 = 1.51 × 10^24 formula units
  • H2O = 239.2/18 × 6.02 × 10^23 = 2.57 × 10^24 formula units
  • Fe = 239.2/56 × 6.02 × 10^23 = 2.57 × 10^24 formula units

In conclusion, the number of formula units is derived from the moles and Avogadro number.

Learn more about formula units at: brainly.com/question/24529075

#SPJ1

6 0
2 years ago
In an endothermic reaction, a drop in temperature would be observed.<br><br> TRUE<br> or <br> FALSE
zvonat [6]
The answer is True! Hope this helps correct me if I’m wrong
8 0
3 years ago
Read 2 more answers
Other questions:
  • Which elements has the largest atomic radius
    6·1 answer
  • After balancing the equation, what would be the coefficient for water? <br> __NH3+__O2=__NO+H2O
    12·1 answer
  • Anne brought a 1 L bottle of vinegar from home to use in an experiment on volcanoes in science class. she poured the contents of
    5·1 answer
  • An unknown compound was decomposed into 63.2 g carbon, 5.26 g hydrogen, and 41.6 g oxygen. what is its empirical formula?
    15·1 answer
  • Write a short explanation about the “cheater” way to find the # of valence electrons an element has, and explain what valence el
    5·1 answer
  • What thype of bond requires the give and take of electrons ?
    12·2 answers
  • If a liquid has a volume of 5800 mL and you need the mass in Liters, will the number appear to
    11·1 answer
  • WILL GIVE BRAINLIEST
    9·1 answer
  • Take zinc-73 through beta decay ; write a complete equation
    15·1 answer
  • the mass by mass percentage of a solution is 20%. find the mass of the solute dissolved in 500g of solution​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!