B when the amount of available plankton is greatly reduced. This would increase fighting among fish for food.
Answer:
24.5g
Explanation:
Given parameters:
Mass of oxygen gas = 21.8g
Unknown:
Mass of water = ?
Solution:
This problem deals with the decomposition of water;
Reaction equation;
2H₂O → 2H₂ + O₂
2 mole of water will produce 1 mole of oxygen gas
First find the number of mole of the oxygen gas given;
Number of moles =
molar mass of O₂ = 2(16) = 32g/mol
Number of moles of O₂ = = 0.68moles
1 mole of oxygen gas will be produced from 2 mole of water
0.68moles of oxygen gas will be produce from 0.68 x 2 moles of water; = 1.36moles of water
Mass of water = number of moles x molar mass
Molar mass of water = 2(1) + 16 = 18g/mol
Mass of water = 1.36 x 18 = 24.5g
Answer:
Joseph Black discovered carbon dioxide.
Explanation:
I think it's the Pentium up
115
<span>he's in the 15th column, 7th period </span><span />
Answer:
a) D = 33.44 Lbmol/h
⇒ B = 62.56 Lbmol/h
b) D = 16.848 Kmol/h
⇒ B = 28.152 Kmol/h
Explanation:
global balance:
- F = D + B........................(1)
∴ F = 100 Lbmol/h
balance per component:
A: 0.4*F = 0.9*D + 0.1*B = 0.4*100 = 40 Lbmol/h..............(2)
B: 0.6*F = 0.1*D + 0.9*B = 0.6*100 = 60 Lbmol/h..............(3)
from (2):
⇒ 0.9*D = 40 - 0.1*B
⇒ D = ( 40 - 0.1*B ) / 0.9............(4)
(4) in (3):
⇒ 0.1*((40-0.1*B)/0.9) + 0.9*B = 60
⇒ B = 62.56 Lbmol/h............(5)
(5) in (1):
⇒ D = 100 - B
⇒ D = 37.44 Lbmol/h
∴ Lbmol = 0.45 Kmol
⇒ B = 62.56 Lbmol/h * ( 0.45 Kmol/ Lbmol ) = 28.152 Kmol/h
⇒ D = 37.44 Lbmol/h * ( 0.45 Kmol/h ) = 16.848 Kmol/h