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Marat540 [252]
4 years ago
12

If b does not equal 0​, can the solution set of ax = b be a plane through the​ origin?

Mathematics
1 answer:
madam [21]4 years ago
8 0

If b does not equal 0​, can the solution set of ax = b be a plane through the​ origin

A plane pass through the origin mean it passes (0,0)

When we plug in 0 for x  then ax=b becomes

a(0) = 0 , when x = 0 then b not equal to 0 is a contradiction .

So , it is not possible if b does not equal 0​, can the solution set of ax = b be a plane through the​ origin.

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lina2011 [118]

Answer:

84x+50

Step-by-step explanation:

First, you would find the area of the entire square. The area of a square is LW, so you would multiply (7x+6)(7x+6). For this, I would use the FOIL method, so you would multiply the first terms which would be (7x)(7x)=14x^2. Then the outside terms, so (7x)(6)=42x. Then the inside, so (7x)(6)=42x. Finally, the last terms, 6(6)=36.

Then you would combine them, so the area of the whole square is 14x^{2} +42x+42x+36 which would equal 14x^{2} +84x+36.

Then, the area of the smaller square is (x)(x) which would equal x^{2}.

Then you would subtract the smaller square from the bigger one, so the final answer would be 14+84x+36 which you could simplify to 84x+50

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ollegr [7]

Answer:

4x^2 + 4x -2

Step-by-step explanation:

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8 0
3 years ago
Can someone help me
kramer

Answer:

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Step-by-step explanation:

JGN is congruent to AIW and the names of the triangles are both in the same order. That may sound confusing but this means that:

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So, if angle N is 134 then angle W is the same.

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Answer:

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Step-by-step explanation:

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