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3 years ago

-8(20 - 3b) - 5(6b - 4a)

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

4 0

Answer:

=20a−6b−160

Step-by-step explanation

−8(20−3b)−5(6b−4a)

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Which label on the cone below represents the center of the base? D B Ο Α OB

Firlakuza [10]

Answer:

Step-by-step explanation:

The center of the base is the center of the circle

The center of the circle is C

8 0

2 years ago

15. The height and yolume of a cylinder are 4cm and 616cm respectively. Calculate the diameter of the base. (take t = 27 쪽 A. 7c

irakobra [83]

Step-by-step explanation:

Given that,

Height of cylinder = 4 cm
Volume of cylinder = 616 cm³

To find,

Diameter of the base = ?

Firstly we'll find the base radius of the cylinder.

$\longmapsto\rm{V_{(Cylinder)} = \pi r^2h}\\$

According to the question,

$\longmapsto\rm{616= \dfrac{22}{7} \times r^2 \times 4}\\$

$\longmapsto\rm{616 \times 7 = 22 \times r^2 \times 4}\\$

$\longmapsto\rm{4312 = 88 \times r^2 }\\$

$\longmapsto\rm{\cancel{\dfrac{4312}{88}} = r^2 }\\$

$\longmapsto\rm{49 = r^2 }\\$

$\longmapsto\rm{\sqrt{49} = r }\\$

$\longmapsto\rm{7 \; cm = r }\\$

Now,

$\longmapsto\rm{Diameter = 2r }\\$

$\longmapsto\rm{Diameter = 2(7 \; cm) }\\$

$\longmapsto\bf{Diameter = 14 \; cm}\\$

The required answer is 14 cm.

4 0

3 years ago

One number is 7 less than another. If 4 times the smaller number plus 2 times the larger number is 62, find the two numbers.

Nana76 [90]

X=Y-7

4X+2Y=62

4(Y-7)+2Y=62

4Y-28+2Y=62

6Y=62+28

6Y=90

Y=90/6

Y=15
Larger number^

X=15-7=8
Smaller number^
PROOF:
4*8+2*15=62

32+30=62

62=62
Hope this helps.

4 0

3 years ago

Determine the value of k

KATRIN_1 [288]

Answer:

$\displaystyle k = 6$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Functions
Function Notation

Algebra II

Piecewise Functions

Calculus

Limits
Continuity

Step-by-step explanation:

Step 1: Define

Identify

Continuous at x = 2

$\displaystyle f(x) = \left \{ {{2x^2 \ if \ x < 2} \atop {x + k \ if \ x \geq 2}} \right.$

Step 2: Solve for k

Definition of Continuity: $\displaystyle \lim_{x \to 2^+} 2x^2 = \lim_{x \to 2^-} x + k$
Evaluate limits: $\displaystyle 2(2)^2 = 2 + k$
Evaluate exponents: $\displaystyle 2(4) = 2 + k$
Multiply: $\displaystyle 8 = 2 + k$
[Subtraction Property of Equality] Subtract 2 on both sides: $\displaystyle 6 = k$
Rewrite: $\displaystyle k = 6$