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3 years ago

2 5 x+y=3 How do u solve please help lol ?

Mathematics

1 answer:

Advocard [28]3 years ago

6 0

Answer:

that question kinda have alot of answers but try y=-25x+31

Step-by-step explanation:

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9966 [12]

Answer:

4:3 or 4 to 3

Step-by-step explanation:

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3 years ago

Find dy/dx and d2y/dx2, and find the slope and concavity (if possible) at the given value of the parameter. (If an answer does n

ella [17]

Answer:

The slope of the function is ²/₃ and since the second derivative is zero, the concavity doesn't exist.

Step-by-step explanation:

Given;

x = 6t

y = 4t - 3

point t = 4

$\frac{dy}{dx} = (\frac{dy}{dt} )/(\frac{dx}{dt} )=\frac{\frac{dy}{dt} }{\frac{dx}{dt}} \\\\\frac{dy}{dt} = 4; \frac{dx}{dt} = 6\\\\\frac{dy}{dx} =\frac{4}{6} = \frac{2}{3}$

The slope of the function is ²/₃

take the second derivative of the function;

the second derivative will be zero since the first derivative is a constant value.

$\frac{d^2y}{dx^2} = 0$

Since the second derivative is zero, the concavity doesn't exist.

4 0

4 years ago

type the slope intercept equation of the line that passes through the point (1,1)&(7,4) enter fraction in simplest form

9966 [12]

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 1}}\quad ,&{{ 1}})\quad 
% (c,d)
&({{ 7}}\quad ,&{{ 4}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{4-1}{7-1}\implies \cfrac{3}{6}\implies \cfrac{1}{2}$

$\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-1=\cfrac{1}{2}(x-1)\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-1=\cfrac{1}{2}x-\cfrac{1}{2}\implies y=\cfrac{1}{2}x-\cfrac{1}{2}+1\implies y=\cfrac{1}{2}x+\cfrac{1}{2}$

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3 years ago

Rhombus ABCD has vertices at (-6, 0),(0,8), (6,0), and (0, -8).

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A’ -9,0. B’ 0,12. C’ 9,0. D’ 0, -12. As long as u put the in order when u listed them that’s the way I put them.

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3 years ago

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cupoosta [38]

First term, n=1: 2*1 -3 = -1

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3 years ago