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Gennadij [26K]
3 years ago
10

. On a school field trip, the school requires that there are 6 teachers for every 90 students. If 135 students attend the trip h

ow many teachers are needed? Write and solve a proportion showing your work. (3 points)
Mathematics
1 answer:
mr_godi [17]3 years ago
5 0

Answer:

For 135 students , the number of teacher requires is 9

Step-by-step explanation:

Given as :

The number of teacher = 6

The number of student  = 90

∵     For 90 students , the number of teacher requires = 6

So , For 1 student , the number of teacher requires = \frac{6}{90}

                                                                                     = \frac{1}{15}

∴   For 135 student , the number of teacher requires =  \frac{1}{15}×135

Or, For 135 student , the number of teacher requires =  \frac{135}{15}

So, For 135 student , the number of teacher requires = 9

Hence For 135 students , the number of teacher requires is 9   Answer

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AT&T would like to test the hypothesis that the proportion of 18- to 34-year-old Americans that own a cell phone is less tha
Vera_Pavlovna [14]

Answer:

The null and alternative hypothesis can be written as:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of 18- to 34-year-old Americans that own a cell phone is less than the proportion of 35- to 49-year-old Americans.

This claim will be reflected in the alternnative hypothesis, that will state that the population proportion 1 (18 to 34) is significantly smaller than the population proportion 2 (35 to 49).

On the contrary, the null hypothesis will state that the population proportion 1 is ot significantly smaller than the population proportion 2.

Then, the null and alternative hypothesis can be written as:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0

The significance level is assumed to be 0.05.

The sample 1, of size n1=200 has a proportion of p1=0.63.

p_1=X_1/n_1=126/200=0.63

The sample 2, of size n2=175 has a proportion of p2=0.68.

p_2=X_2/n_2=119/175=0.68

The difference between proportions is (p1-p2)=-0.05.

p_d=p_1-p_2=0.63-0.68=-0.05

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{126+119}{200+175}=\dfrac{245}{375}=0.653

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.653*0.347}{200}+\dfrac{0.653*0.347}{175}}\\\\\\s_{p1-p2}=\sqrt{0.001132+0.001294}=\sqrt{0.002427}=0.049

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.05-0}{0.049}=\dfrac{-0.05}{0.049}=-1.01

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

\text{P-value}=P(z

As the P-value (0.1554) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the proportion of 18- to 34-year-old Americans that own a cell phone is less than the proportion of 35- to 49-year-old Americans.

5 0
3 years ago
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