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NARA [144]
3 years ago
12

-

Mathematics
1 answer:
posledela3 years ago
3 0

Answer:

The bakery will bake 600 butterscotch bread, 550 chocolate bread, and 1,000 coconut bread

Step-by-step explanation:

In order to answer the word problem question, we list the parameters as follows;

The number of bread types the bakery takes = 3 types of bread

The monthly cost of the bakery for baking the bread, C = RM 6,850

The number of bread loaves baked = 2,150

The cost of baking a loaf of butterscotch bread = Rm 2

The cost of baking a loaf of chocolate bread = Rm 3

The cost of baking a loaf of coconut bread = Rm 4

The sale price of a butterscotch bread = Rm 3

The sale price of a chocolate bread = Rm 4.50

The sale price of a coconut bread = Rm 5

The amount of monthly profit the bakery makes, P = Rm 2,975

Therefore, the total revenue of the company, R = C + P

∴ R = Rm 6,850 + Rm 2,975 = Rm 9,825

Let 'x', 'y', and 'z', represent the number of loaves of butterscotch, chocolate, and coconut bread the company bakes respectively

Then we get;

x + y + z = 2,150...(1)

2·x + 3·y + 4·z = 6,850...(2)

3·x + 4.5·y + 5·z = 9,825...(3)

Multiplying equation (1) by 2 and subtracting from equation (2) gives;

2·x + 3·y + 4·z - 2×(x + y + z) = 6,850 - 2 × 2,150 = 2,550

2·x - 2·x + 3·y - 2·y + 4·z - 2·z = 2,550

∴ y + 2·z = 2,550...(4)

Adding equation (1) to (2) and subtracting from (3) gives;

3·x - 3·x + 4.5·y - 4·y + 5·z - 5·z = 9,825 - (6,850 + 2,150) = 825

1.5·y = 825

y = 825/1.5 = 550

The number of loaves of chocolate bread baked, y = 550

From equation (4), we get;

550 + 2·z = 2,550

2·z = 2,550 - 550 = 2,000

z = 2,000/2 = 1,000

The number of loaves of coconut bread baked, z = 1,000

∴ From equation (1) x = 2,150 - (550 + 1,000) = 600

The number of loaves of butterscotch bread baked, x = 600.

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Part A

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Kelsey made a mistake on line 3. Note how the 17/6 flips to 6/17. This is not correct. You keep the first fraction the same, but you do flip the second fraction. This only applies when you divide two fractions.

The third step should look like -\frac{17}{6}\times \frac{3}{4}

=======================================================

Part B

Here's what she should have written

-2 \frac{5}{6} \div 1 \frac{1}{3}\\\\-\frac{17}{6} \div \frac{4}{3}\\\\-\frac{17}{6} \times \frac{3}{4}\\\\-\frac{17\times 3}{6\times 4}\\\\-\frac{51}{24}\\\\-\frac{17}{8}\\\\

If you want to convert that improper fraction to a mixed number, then you could do something like this

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