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beks73 [17]
3 years ago
10

The McPhearson family went fishing. They caught 7 fish. The weights of the fish were 15, 16, 15, 13, 19, 20, and 21 pounds. What

is the mean weight of these fish? Answer options with 4 options A. 15 B. 16 C. 17 D. 18
Mathematics
1 answer:
Irina18 [472]3 years ago
3 0

Answer:

C. 17

Step-by-step explanation:

The mean weight can be calculated by adding the numbers 15 + 16 + 15 + 13 + 19 + 20 + 21 divided by the number 7, which is the amount of numbers you just added.

(15 + 16 + 15 + 13 + 19 + 20 + 21)/7

the outcome = 17 which corresponds to answer C.

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Question 6 of 10 The triangles shown below may not be congruent. 1) 25° 55° 100° 100° 66° 25° O A. True O B. False​
Blizzard [7]

Answer:

True, they may not be congruent

Step-by-step explanation:

A figure cannot be determined as congruent from three angles alone. In order  for two shapes to be congruent, all corresponding parts must be congruent. This means all the sides and angles of the two shapes must be the same in order for the two shapes to be congruent. If we know all the angles are the same, the sides could still be different lengths, so this does not prove congruency.

5 0
3 years ago
Please help ! I don’t get it!
Amiraneli [1.4K]

Answer:

PR = 16

SR = 12

Step-by-step explanation:

6/8 = (x-3)/(x+1)

8x-24 = 6x+6

simplify

2x = 30

x = 15

PR = 15 + 1 = 16

SR = 15 - 3 = 12

8 0
2 years ago
Someone help me please
Ivahew [28]

Answer:

This is the answer48 cm²

6 0
3 years ago
Read 2 more answers
Helpppppppppppppppppp​
Marianna [84]

Answer:

Step-by-step explanation:

3/8 if you change 1/4 to 8ths you get 2/8. so if you add 1 3/8 + 2/8 you get 1 5/8 so you only need 3/8 to get to 2 quarts.

3 0
2 years ago
The bases of a trapezoid lie on the lines y=2X +7 and y= 2X -5. Write the equation that contains the midsegment of the trapezoid
ryzh [129]

Given:

The bases of a trapezoid lie on the lines

y=2x+7

y=2x-5

To find:

The equation that contains the midsegment of the trapezoid.

Solution:

The slope intercept form of a line is

y=mx+b

Where, m is slope and b is y-intercept.

On comparing y=2x+7 with slope intercept form, we get

m_1=2,b_1=7

On comparing y=2x-5 with slope intercept form, we get

m_2=2,b_2=-5

The slope of parallel lines are equal and midsegment of a trapezoid is parallel to the bases. So, the slope of the bases line and the midsegment line are equal.

m=m_1=m_2=2

The y-intercept of one base is 7 and y-intercept of second base is -5. The y-intercept of the midsegment is equal to the average of y-intersects of the bases.

b=\dfrac{b_1+b_2}{2}

b=\dfrac{7-5}{2}

b=\dfrac{2}{2}

b=1

So, the y-intercept of the required line is 1.

Putting m=2 and b=1 in slope intercept form, we get

y=2x+1

Therefore, the equation of line that contains the midsegment of the trapezoid is y=2x+1.

7 0
2 years ago
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