All categories

2 years ago

Could use the help! thanks again!

Mathematics

1 answer:

love history [14]2 years ago

5 0

Answer:

Beth is incorrect.

It is a translate to the right 5 units and up 1 unit.

When we solve x-5=0 we get x=5, not x=-5 which says we go right 5 units.

When we plug in 5 into the expression for g, we get 1 which means go up 1 as well.

Step-by-step explanation:

So $g(x)=\sqrt{x-5}+1$ is actually a translated 5 units and up 1 unit. Why?

Let's take there point (0,0) and figure out what the new point is on the translated graph.

We need to figure out when the inside of our square root for g is 0. This is where the graph of g will start at and continue on.

x-5=0 when x=5 ( I added 5 on both sides).

So let's plug in 5 to see what the new point is.

$g(5)=\sqrt{5-5}+1$

$g(5)=\sqrt{0}+1$

$g(5)=0+1$

$g(5)=1$

So the new graph, g, starts at the point (5,1).

You might be interested in

Please help me with this question I will give you 66 points

Leokris [45]

Answer:

What is the question?

7 0

3 years ago

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

2 years ago

If A= [-5,7] and B= [6,10], then find A u B

lesantik [10]

Answer:

$\large\boxed{A\ \cup\ B=[-5,\ 10]}$

Step-by-step explanation:

Look at the picture.

The union of two sets A and B (A ∪ B) is the set of elements which are in A, in B, or in both A and B

7 0

3 years ago

Simplify the midpoint of QS.

oee [108]

Answer:

[(a + b), c]

Step-by-step explanation:

Midpoint of a segment with extreme ends represented by ordered pairs $(x_1,y_1)$ and $(x_2,y_2)$ ,

Midpoint = $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

It is given that extreme ends of the segment QS are Q(2b, 2c) and S(2a, 0)

Coordinates of the midpoint of QS will be,

= $(\frac{2a+2b}{2},\frac{2c+0}{2} )$

= [(a + b), c]

Therefore, ordered pair representing the midpoint of QS will be [(a + b), c].

8 0

3 years ago

A magazine has 5,580,000 subscribers this year. This number is down 7% from last year. How many subscribers were there last year

cestrela7 [59]

I got the answer C. This was by multiplying .07 (the decrease) by 5,580,000. Which I then got the number 390,600, which I added to 5,580,000.

6 0

3 years ago