Question

Could use the help! thanks again!

Answer 1

Answer:

Beth is incorrect.

It is a translate to the right 5 units and up 1 unit.

When we solve x-5=0 we get x=5, not x=-5 which says we go right 5 units.

When we plug in 5 into the expression for g, we get 1 which means go up 1 as well.

Step-by-step explanation:

So $g(x)=\sqrt{x-5}+1$ is actually a translated 5 units and up 1 unit. Why?

Let's take there point (0,0) and figure out what the new point is on the translated graph.

We need to figure out when the inside of our square root for g is 0.  This is where the graph of g will start at and continue on.

x-5=0 when x=5 ( I added 5 on both sides).

So let's plug in 5 to see what the new point is.

$g(5)=\sqrt{5-5}+1$

$g(5)=\sqrt{0}+1$

$g(5)=0+1$

$g(5)=1$

So the new graph, g, starts at the point (5,1).