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3 years ago

-k/7=-4 i dont know how to do one step equations

2 answers:

8 0

Hello there!

To solve this equation for the variable k, you must isolate k so that it is set equal to a value. To start, first multiply both sides by 7 to get rid the 7 in the denominator:
7(-k/7)=7(-4)

This would result in -k=-28.

The next step would be to divide both sides by -1 as we still need to fully isolate the value of k:
-k/-1=-28/-1

This would result in your answer, k=28

Now, to check that 28 is the correct value of k, plug 28 back into the original equation to see if you get a result of -4=-4:

-(28)/7=-4
-28/7=-4
-4=-4

Now that you have confirmed k=28, you can conclude that that would be your answer.

Hope this helps!

AnnyKZ [126]3 years ago

5 0

-k/7 = -4

k/7 = 4

k = 7 × 4

k = 28

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The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C: [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

Sample size n > 30
Sample mean = $\overline{x}$
Sample standard deviation = s
Population standard deviation = $\sigma$
Level of significance = $\alpha$

Then the confidence interval is obtained as

Case 1: Population standard deviation is known

$\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}$

Case 2: Population standard deviation is unknown.

$\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}$

For this case, we're given that:

Sample size n = 90 > 30
Sample mean = $\overline{x}$ = 138
Sample standard deviation = s = 34
Level of significance = $\alpha$ = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: $Z_{0.1/2}$ = ±1.645

Thus, we get:

$CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]$

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C: [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

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