Answer:
It's A. 28 degrees
Step-by-step explanation:
First, you determine the angle measure directly below x. That is a straight line, so it measures 180 degrees. You can add 38 and 90 degrees, and then subtract from 180 to get the last angle measure. This gives you 52. The right 3 angles measure 90 degrees, because they are on the opposite side of a right angle marker. You can add 10 and 52 and then subtract from 90 to get the missing x value, 28.
These numbers are categorized as numerical coefficients. A number that is next to a specific variable in an algebraic or polynomial expression and is essentially being multiplied to that variable.
Try this option:
According to property such triangle
1. area=0.5*a*b, where a and b - the sides of angle 90°.
Using this equation: 180=0.5*40*b, ⇒ b=9.
2. c²=a²+b², ⇒c=√(9²+40²)=41 - the third side of the triangle;
3. Perimeter=a+b+c=9+40+41=90 cm.
answer: 90 cm.
Answer: The graph in the bottom right-hand corner
(see figure 4 in the attached images below)
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Explanation:
Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.
Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.
After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.
Do lulus way. If you change the angles, you will not have a pentagon anymore. If you subtract, it wouldn’t be the same ratio:)