What are the solutions of 12 – x2 = 0? x = 2 StartRoot 3 EndRoot and x = Negative 2 StartRoot 3 EndRoot x = 3 StartRoot 2 EndRoo
t and x = Negative 3 StartRoot 2 EndRoot x = 4 StartRoot 3 EndRoot and x = Negative 4 StartRoot 3 EndRoot x = 6 and x = –6
2 answers:
Answer:
±2 sqrt(3) = x
Step-by-step explanation:
12 -x^2 =0
Add x^2 to each side
12 -x^2+x^2 =0+x^2
12 = x^2
Take the square root of each side
±sqrt(12) = sqrt(x^2)
We know that sqrt(ab) = sqrt(a) sqrt(b)
±sqrt(4*3) = sqrt(x^2)
±sqrt(4) * sqrt(3) = x
±2 sqrt(3) = x
Answer:
A)
x = 2 StartRoot 3 EndRoot and x = Negative 2 StartRoot 3 EndRoot
Step-by-step explanation:
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Hope this helps!
