A. 7x
B. 8x-1
C. 6x+12
D. 3x +4
E. 13x-7
30 times 30 plus 45 minus 456 is 489
Ok,
f(0.35)= 7f/20
f(-5.2)=-26f/5
f(10)= 10f
f(-0.5)= -f/2
as for the last question I am not quite sure, sorry....hope I helped a little :)
A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
