To put together or pair something...
Answer:
The center of that class, which is the sum of its largest and smallest values divided by 2 ⇒ E
Step-by-step explanation:
* Lets explain what is the class mid-point
- It is defined as the average of the upper and lower class limits
- The class midpoint is the lower class limit plus the upper class limit
divided by 2
- The easiest way to find the class mid-point is to add the upper
and lower boundary and divide your answer by two
- The lower limit for every class is the smallest value in that class.
- The upper limit for every class is the greatest value in that class
* <u><em>Lets solve the problem</em></u>
- It is not the largest value of that class minus the class width
- Its not the difference between the largest and smallest values of
that class
- It is not the difference between the largest and smallest values of
that class divided by 2
- It is the center of that class, which is the sum of its largest and
smallest values divided by 2
Answer:
7
Step-by-step explanation:
Answer:
width of the border is 3 inches
Step-by-step explanation:
Given data
size = 8 inches by 10 inches
area = 144 square inches
to find out
width of the border
solution
first we consider width of border is x
area of new full rectangle = (8 + 2x ) × ( 10 + 2x )
so we know area of photo = 8 × 10 = 80 square inches
and area of border = 144 square inches that is given
so new area of photo with the border is 80 + 144 = 224 square inches
and we can say that
area of full rectangle - area of the photograph = Area of Border
(8 + 2x) × (10 + 2x) – (80) = 144 square inches
80 + 16x + 20x + 
– 80 = 144
+ 36x – 144 = 0
solve thios equation we get
+ 9x – 36 = 0
solve thios equation we get
(x + 12) (x – 3) = 0
so here x have two value one is negative and other is positive
so we consider only positive value
x = -12 or x = 3
width of the border is 3 inches
Let x be a random variable representing the price of a Congo-imported black diamond. Let the higher price be p. Then,
P(x < p) = P(x < (p - mean)/sd) = P(x < (p - 60,430)/21,958.08) = P(z < 2)
Therefore,
(p - 60,430)/21,958.08 = 2
p - 60,430 = 2 x 21,958.08 = 43,916.16
p = 34,916.16 + 60,430 = 104.346.16
Therefore, The required price is $104,346.16
