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fiasKO [112]
3 years ago
13

One angle is four times as large as a second angle of the angles are supplementary find the number of degrees in the smaller ang

le
Mathematics
1 answer:
seropon [69]3 years ago
6 0

let x=smaller angle

 

larger angle=4x

x+4x=180

5x=180

x=180/5

x=36

smaller angle=36º

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Step-by-step explanation:

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What is the answer of this? thanks. 15 pts
Vikentia [17]
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What is the slope intercept form of the equation 4x-8y=72
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Answer:

y = 1/2x - 9

General Formulas and Concepts:

<u>Alg I</u>

Standard Form: Ax + By = C

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Standard Form: 4x - 8y = 72

<u>Step 2: Find slope-intercept form</u>

  1. Subtract 4x on both sides:          -8y = 72 - 4x
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Which inequality is NOT true if y= -5​
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Step-by-step explanation:

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3 years ago
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0
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