Answer: c I believe
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.
Answer:
24x + 41
Step-by-step explanation:
Distribute the 6.
6(4x + 5) + 11 = 24x + 30 + 11
Now we just add the 30 and the 11 which are at the back of the expression.
24x + 30 + 11 = 24x + 41
Therefore the answer is 24x + 41. Please mark brainliest if possible and i hope you get a good grade on your homework
<span>The elevation is 12,000 feet. the altimeter reading in an airplane is 17.00 in hg. this pressure is equal to:
There are 29.92inHg in 1 atm
thus
</span>17 inHg×(1 atm/29.92inHg)
=17/29.92
=0.5682 atm
Answer: 0.5682 atm
Answer:
yes, your right
Step-by-step explanation: