Answer:
12
Step-by-step explanation:
Answer:
She either trained recently in an area with a high elevation, participated in blood doping, or has polycythemia vera.
Step-by-step explanation:
Michaela has a hematocrit value of 59%, which is well above the normal range, according to research that has found that athletes reduce hematocrit levels in the form of sports anemia.
This sports anemia is caused by increasing plasma volume into RBCs and increasing the total mass of hemoglobin.
But Michella has a significant increase in hematocrit rather than the normal range.
so hematocrit value suggest blood dopping which has resultted into increased hematocrit level
Answer:
The ira will contain $228,278.05 when he retires at age 65. This is 6.04 times the amount of money he deposited.
Step-by-step explanation:
In order to solve this problem, we can make use of the following formula:
![FV=PMT[\frac{(1+i)^{n}-1}{i}]](https://tex.z-dn.net/?f=FV%3DPMT%5B%5Cfrac%7B%281%2Bi%29%5E%7Bn%7D-1%7D%7Bi%7D%5D)
Where:
FV= Future value of the ira
PMT= the amount of money you deposit each month
i= is the interest rate per period
n=number of periods
in this case we will assume the interest will be compounded each month.
So:
FV this is what we need to know.
PMT= $75 the amount he will deposit each month
t = 42 years,
this is 65-23=42
n=42 years * 12 months/year = 504 months
i=0.07/12
So we can now use the given formula:
![FV=PMT[\frac{(1+i)^{n}-1}{i}]](https://tex.z-dn.net/?f=FV%3DPMT%5B%5Cfrac%7B%281%2Bi%29%5E%7Bn%7D-1%7D%7Bi%7D%5D)
![FV=75[\frac{(1+\frac{0.07}{12})^{504}-1}{\frac{0.07}{12}}]](https://tex.z-dn.net/?f=FV%3D75%5B%5Cfrac%7B%281%2B%5Cfrac%7B0.07%7D%7B12%7D%29%5E%7B504%7D-1%7D%7B%5Cfrac%7B0.07%7D%7B12%7D%7D%5D)
So we get:
FV=$228,278.05
which is the amount of money he will have after 42 years.
In total, he deposited:
$75*504months = $37,800
so he will have:
times the amount of money he deposited throughout this time.
A pair of congruent triangles will have the same three side lengths and the same the angles. The equal sides and angles may not be in the same position due to turning or flipping, but they are always there. You can draw a phone with congruent lines on each triangle.
I hope this helps
Lets imagine the shape
M
/\
/ | \
/ | \
/ | \
P /___ |___\ N
O
Now in If we take â†MOP and â†MON
As MO ⊥ NP so â MON=â MOP
NO=NP (given)
And MO is a common side
so by side angle side rule of congruency
â†MOP and â†MON are congruent
so MP is congruent to MN