Answer:
1. A(-12,-14),B(8,-4),C(0,14)
2. A(-24,-28), B(4,-2),C(0,7)
3. A(-6,-7), B(4,-2), C(0,7)
4. A(-24, -14), B(16,,-4),C(0,14)
Step-by-step explanation:
Each x and y are multiplied by the scale factor of 2
p(2) =147 and p(4) = 1791
We are given p(x)= 6x^4 + 4x^3 – 3x^2 + 8x + 15.
Now we need to find value of p(2) and p(4)
Put x =2,
p(2) = 6(2)^4 + 4(2)^3 – 3(2)^2 + 8(2) + 15
p(2) = 6(16)+4(8)-3(4)+8(2)+15
p(2) = 96+32-12+16+15
p(2) = 147
Now put x = 4
p(4) = 6(4)^4 + 4(4)^3 – 3(4)^2 + 8(4) + 15
p(4) = 6(256)+4(64)-3(16)+8(4)+15
p(4) = 1536+256-48+32+15
p(4) = 1791
B
so 8(2)=16=5x-4
5x=20
x=4
so B
I think it is associative! Not sure though bc of the q!
370.85
20.50×10. +165.85=
