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AURORKA [14]
3 years ago
10

Please help!! 15 points!

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
6 0
The answer is A( -12, -14), B( 8, -4), C(0, 14)
AVprozaik [17]3 years ago
4 0

Answer:

1. A(-12,-14),B(8,-4),C(0,14)

2. A(-24,-28), B(4,-2),C(0,7)

3. A(-6,-7), B(4,-2), C(0,7)

4. A(-24, -14), B(16,,-4),C(0,14)

Step-by-step explanation:

Each x and y are multiplied by the scale factor of 2

You might be interested in
Use properties to compare expression 5 x ( 6 x 3 )and ( 5 x 6) x 3
nadya68 [22]
5(6*3) = 5(18) = 90

(5*6)3 = (30)3 = 90

The answer is the same by the associative law.
6 0
3 years ago
Simplify completely quantity 2 x squared plus 13 x plus 20 all over x squared minus 5 x minus 36 .
adoni [48]

Answer:

  • (2x + 5)/(x - 9)
  • 3. quantity 2 x plus 5 over x minus 9

Step-by-step explanation:

Quantity 2 x squared plus 13 x plus 20 all over x squared minus 5 x minus 36

  • (2x² + 13x + 20)/(x² -5x - 36) =
  • (2x²+ 5x + 8x + 20)/(x² - 9x + 4x -36)=
  • (2x + 5)(x + 4)/(x - 9)(x + 4) =
  • (2x + 5)/(x - 9)

Correct option is option 3

3 0
4 years ago
If f(x) = 8 – 10x and g(x) = 5x + 4, what is the value of (fg)(–2)?
Vedmedyk [2.9K]
F(x) = 8 - 10x

g(x) = 5x + 4

Finding (fg)(-2).

First let us find fg(x),  this is the same as f(g(x))

f(g(x))

f(5x + 4)

Recall, f(x) = 8 - 10x, therefore f(5x + 4) would be such that anywhere we see x in the f(x), we replace it with 5x + 4

f(x) = 8 - 10x

f(5x +4) =  8 - 10(5x + 4)

             =  8 - 50x - 40

             = -50x + 8 - 40

             =  -50x - 32

f(g(x)) = fg(x) = -50x - 32

fg(-2) = -50*(-2) - 32 = 100 - 32 = 68

Therefore fg(-2) = 68

I hope this helped.
5 0
3 years ago
Select the correct product. (5m2 - 2m + 1)(3m - 4) 15m3 - 26m2 + 5m - 4 15m3 - 26m2 + 11m - 4 15m3 - 14m2 + 11m + 4 15m3 - 14m2
Masteriza [31]
<span>15m3 - 26m2 + 11m - 4</span>
7 0
3 years ago
Read 2 more answers
What is the right-hand limit of as x approaches f(x) = x/x-5 as x approaches 5?
Ber [7]

Answer:

+\infty

Step-by-step explanation:

The expression for the right hand limit of f(x) is:

f = \frac{x+\epsilon}{x + \epsilon - 5}

The expression can be simplified with some algebraic handling:

f = \frac{1}{\frac{x+\epsilon-5}{x+\epsilon} }

f = \frac{1}{1-\frac{5}{x+\epsilon} }

Let be x = 5, as \epsilon is approaching zero, f is positive and becomes bigger, diverging to +\infty.

7 0
3 years ago
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