The 10 tons should have 37.9% cement.
Let the 25% mixture be x tons
Then the 68% mixture will be (10 -x) tons.
Using formula for mixtures:
Let p for percentage and w for weight in tons.
p₁w₁ + p₂w₂ = pw
25*x + 68*(10-x) = 37.9*10
25x + 680 - 68x = 379
680 - 43x = 379
680 - 379 = 43x
301 = 43x
43x = 301
x = 301/43
x = 7
Recall that x, was for the 25% mixture, 7 tons.
a) For the 68% mixture, = 10 - x = 10 -7 = 3 tons.
b) For the 25% mixture = x = 7 tons.
$23.1 i think is the answer not sure
Answer:
Car 1 : 40 miles per gallon
Car 2: 25 miles per gallon
Step-by-step explanation:
family has two cars. During one particular week, the first car consumed 15 gallons of gas. The second car consumed 25 gallons of gas. The two cars Drove a combined total of 1475 miles and the sum of their fuel efficiency was 65 miles per gallon. What were the fuel efficiency of each of the cars that week
Given that :
Fuel efficiency , car 1 = x
Fuel efficiency , car 2 = y
x + y = 65 - - (1)
15x + 35y = 1475 - - - (2)
x = 65 - y
15(65-y) + 35y
975 - 15y + 35y = 1475
20y = 14875 - 975
20y = 500
y = 25
Put y = 25 in (1)
x + y = 65
x + 25 = 65
x = 65 - 25
x = 40
-6 is the answer since it’s closer to zero
$0.31 for each pint hope this helps
