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GaryK [48]
3 years ago
14

Please answer this question only if you know the answer! 25 points and brainliest!

Mathematics
2 answers:
dsp733 years ago
8 0

Answer:

a You must choose at least 3 marbles

Step-by-step explanation:

If the probability is equally likely that you will choose a red or blue marble (1/2)

Then the marbles will need to be the same size or you will know which the color of the marble by the size.

There needs to be the same number of marbles, or you will be more likely to pick the color with more marbles of that color

If you look, you will pick the color of the marble you want.

The probability is determined by the number of marbles in the bag, not by the number you choose

 

AveGali [126]3 years ago
6 0

Answer:

a. You must choose 3 marbels

Step-by-step explanation:


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b= -0.1

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There are 400 students in a school. Fifty five percent are girls. How many boys are there?
ki77a [65]
1) 55% is girls, then 
100-55=45% is boys.

2) 45%=0.45                                     or  2) 400 ----100%
3)400*0.45= 180 boys                                 x -----45%      x=400*45/100=180 boys

Answer is 180 boys.
5 0
3 years ago
What is the slope of a line that passes through the points (-2, 0) and (-4, -3)?
Semmy [17]

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Step-by-step explanation:

3 0
3 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
2 years ago
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