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Natali [406]
3 years ago
10

A circle with radius 3 has a sector with a central angle of 1/9 pi radians

Mathematics
1 answer:
Art [367]3 years ago
5 0

The area of sector is 1.57 m²

<u>Explanation:</u>

Given:

Radius, r = 3 m

Central angle of a sector = 1/9π radians

Area of sector, A = ?

We know:

Area of sector, A = \frac{1}{2} r^2 \alpha

where,

α is the central angle in radians

On substituting the value we get:

A = \frac{1}{2} X(3)^2 X \frac{1}{9}X 3.14\\ \\A = 1.57 m^2

Therefore, the area of sector is 1.57 m²

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Answer:

Therefore the required resulting equation is

6x-15y=-63\\-15x+15y=90

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Step-by-step explanation:

Given:

2x-5y=-21         ......................Equation ( 1 )

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Therefore the required resulting equation is

6x-15y=-63\\-15x+15y=90

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