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3 years ago

What answer question please now

Mathematics

1 answer:

choli [55]3 years ago

8 0

Answer: ·→VW & ·→ VU

Step-by-step explanation: The line starts at the angle, V and t in ou the direction of the arrow to the other point on the line.

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Which angle is an acute angle?

larisa [96]

there is no acute angle.......

4 0

3 years ago

Read 2 more answers

Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.

jek_recluse [69]

Answer:

$\mathbf{a)} \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\\\mathbf{b)} \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee \; F(x)\\\mathbf{c)} \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)\\\mathbf{d)} \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)\\\mathbf{e)} \left((\exists x\in X)C(x) \right) \wedge \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)$

Step-by-step explanation:

Let $X$ be a set of all students in your class. The set $X$ is the domain. Denote

$C(x) - ' \text{$x $ has a cat}'\\D(x) - ' \text{$x$ has a dog}'\\F(x) - ' \text{$x$ has a ferret}'$

$\mathbf{a)}$

Consider the statement 'A student in your class has a cat, a dog, and a ferret'. This means that $\exists x \in X$ so that all three statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

$\left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)$

$\mathbf{b)}$

Consider the statement 'All students in your class have a cat, a dog, or a ferret.' This means that $\forall x \in X$ at least one of the statements C(x), D(x) and F(x) is true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

$\left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee F(x)$

$\mathbf{c)}$

Consider the statement 'Some student in your class has a cat and a ferret, but not a dog.' This means that $\exists x \in X$ so that the statements C(x), F(x) are true and the negation of the statement D(x) . We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

$\left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)$

$\mathbf{d)}$

Consider the statement 'No student in your class has a cat, a dog, and a ferret..' This means that $\forall x \in X$ none of the statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as a negation of the statement in the part a), as follows

$\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)$

$\mathbf{e)}$

Consider the statement ' For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.'

This means that for each of the statements C, F and D there is an element from the domain $X$ so that each statement holds true.

We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

$\left((\exists x\in X)C(x) \right) \wedge \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)$

5 0

4 years ago

A certain forest covers an area of 3700 km. Suppose that each year this area decreases by 5.5%. What will the area be after 15 y

Bess [88]

Answer:

1584 square kilometers.

Step-by-step explanation:

Here's the function I use.

$y=a(1-r)^t$

a= starting amount

r= rate

t= years

First step: $y=3700(1-0.055)^1^5$

Second step: $=3700(0.945)^1^5$

Third step: =1583.72164269

Fourth step: Round to the nearest square kilometer. Since 1583.7 is closer to 1584, you must round up.

Fifth step: The final answer is $1584 km^2$

Hope this helps and stay during these crucial times. We'll get through this!

5 0

3 years ago

1-sin^2x / sin^2x + cos^2x

Hunter-Best [27]

Answer:

Solution answer is $cos^2x$

Step-by-step explanation:

$1-sin^2x = cos^2x$

$sin^2x + cos^2x = 1$

then

$1-sin^2x / sin^2x + cos^2x = cos^2x / 1$

Solution answer is $cos^2x$

5 0

3 years ago

Can anyone please help me with this question??

ANEK [815]

There are many different paths to take but here is my take

15%:22.5%:48%: 74 3/4 Turn everything into a percent
15%:22.5%:48%: 7475% Turn into a decimal
.15: .22: .48: 74.75 Times by 100
15: 22 : 48: 7475 Covert into factors
5(3) : 2(11) : 3(2⁴): 5²(299) Relize there is no common factor...
15: 22 : 48: 7475 <------- Whole numbers

8 0

3 years ago

Read 2 more answers