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Elis [28]
2 years ago
13

Reducible interest at 6% pa is charged on a loan of $50 000. Annual repayments of

Mathematics
1 answer:
Nana76 [90]2 years ago
7 0

1. The loan balance after 2 years is $45,262.

2. The loan balance after 3 years is $42,678.

3. The loan balance after 1 year is $47,700.

<h3>What is the loan balance?</h3>

The loan balance is the amount remaining from the principal amount after the deduction of repayment and the addition of interest for the period.

The loan balance can be computed manually as below:

<h3>Data and Calculations:</h3>

Loan amount = $50,000

Interest rate = 6%

Annual repayments = $5,000

1st year:

Loan amount = $50,000

Repayment = ($5,000)

Interest = $2,700 ($50,000 - $5,000) x 6%

Loan balance = $47,700 ($50,000 - $5,000 + $2,700)

2nd year:

Loan balance = $47,700

Repayment = ($5,000)

Interest = $2,562 ($47,700 - $5,000) x 6%

Loan balance = $45,262 ($47,700 - $5,000 + $2,562)

3rd year:

Loan balance = $45,262

Repayment = ($5,000)

Interest = $2,416 ($45,262 - $5,000) x 6%

Loan balance = $42,678 ($45,262 - $5,000 + $2,416)

Thus, the loan balance after 3 years is $42,678.

Learn more about computing loan balances at brainly.com/question/24576997

#SPJ1

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4 years ago
What is 73 divided by 8 equal in remainder???
olasank [31]

Answer:

9 remainder 1

Step-by-step explanation:

Not sure but uh... 73/8=9 remainder 1.

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4 0
2 years ago
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3 years ago
Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


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3 years ago
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